What is the limit as x approaches 0 of (2x+1)(x-3) ?

The limit as x approaches 0 of (2x+1)(x-3) is -3

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limit as x approaches 0 of (2x+1)(x-3)

x \to 0 lim ((2 x + 1) (x - 3))

- 3

Solution steps

x \to 0 lim ((2 x + 1) (x - 3))

Plug in the value

x = 0

= (2 \cdot 0 + 1) (0 - 3)

Simplify

(2 \cdot 0 + 1) (0 - 3) : - 3

= - 3

\frac{8}{x}

\frac{\partial}{\partial x} (vx)

y^{^{'}} - 2 y = - 3 e^{t}

x \to - 3 lim (\frac{8}{x + 3})

\int_{0}^{2} \frac{1}{1 + e ^{2 x}} d x

What is the limit as x approaches 0 of (2x+1)(x-3) ?
The limit as x approaches 0 of (2x+1)(x-3) is -3