What is (\partial)/(\partial x)(ln(x)-2) ?

The answer to (\partial)/(\partial x)(ln(x)-2) is 1/x

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(\partial)/(\partial x)(ln(x)-2)

\frac{\partial}{\partial x} (ln (x) - 2)

\frac{1}{x}

Solution steps

\frac{\partial}{\partial x} (ln (x) - 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (ln (x)) - \frac{\partial}{\partial x} (2)

\frac{\partial}{\partial x} (ln (x)) = \frac{1}{x}

\frac{\partial}{\partial x} (2) = 0

= \frac{1}{x} - 0

Simplify

= \frac{1}{x}

x \to 1 lim (\frac{2 x}{x ^{2} + x})

\frac{\partial}{\partial y} (- x y)

\frac{d}{d x} ((2 x^{2} + 1)^{4})

\frac{d ^{2}}{d x ^{2}} (e^{- x})

y^{^{'}} = e^{2 x - 1} \cdot y^{2}

What is (\partial)/(\partial x)(ln(x)-2) ?
The answer to (\partial)/(\partial x)(ln(x)-2) is 1/x