What is the derivative of (2x^2+1^4) ?

The derivative of (2x^2+1^4) is 16x(2x^2+1)^3

What is the first derivative of (2x^2+1^4) ?

The first derivative of (2x^2+1^4) is 16x(2x^2+1)^3

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\frac{d}{d x} ((2 x^{2} + 1)^{4})

16 x (2 x^{2} + 1)^{3}

Solution steps

\frac{d}{d x} ((2 x^{2} + 1)^{4})

Apply the chain rule:

4 (2 x^{2} + 1)^{3} \frac{d}{d x} (2 x^{2} + 1)

= 4 (2 x^{2} + 1)^{3} \frac{d}{d x} (2 x^{2} + 1)

\frac{d}{d x} (2 x^{2} + 1) = 4 x

= 4 (2 x^{2} + 1)^{3} \cdot 4 x

Simplify

= 16 x (2 x^{2} + 1)^{3}

\frac{d ^{2}}{d x ^{2}} (e^{- x})

y^{^{'}} = e^{2 x - 1} \cdot y^{2}

\int_{0}^{2} 2 x^{2} d x

\frac{d}{d x} (1 - 2 x^{2})

\frac{d}{d x} (\frac{x}{x ^{3} + 1})

What is the derivative of (2x^2+1^4) ?
The derivative of (2x^2+1^4) is 16x(2x^2+1)^3
What is the first derivative of (2x^2+1^4) ?
The first derivative of (2x^2+1^4) is 16x(2x^2+1)^3