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Popular >

y^'=e^{2x-1}*y^2

Solution

y^{^{'}} = e^{2 x - 1} \cdot y^{2}

Solution

y = - \frac{2}{e ^{2 x - 1} + c _{1}}

Solution steps

y^{'} (x) = e^{2 x - 1} \cdot y^{2}

Solve separable ODE:

y = - \frac{2}{e ^{2 x - 1} + c _{1}}

y = - \frac{2}{e ^{2 x - 1} + c _{1}}

Popular Examples

integral from 0 to 2 of 2x^2

\int_{0}^{2} 2 x^{2} d x

derivative of sqrt(1-2x^2)

\frac{d}{d x} (1 - 2 x^{2})

derivative of (sqrt(x)/(x^3+1))

\frac{d}{d x} (\frac{x}{x ^{3} + 1})

limit as x approaches 2+of 2sqrt(x-2)

x \to 2 + lim (2 x - 2)

tangent of y=sin(sin(x)),(pi,0)tangent of

y = sin (sin (x)), (π, 0)

Frequently Asked Questions (FAQ)

What is the solution for y^'=e^{2x-1}*y^2 ?
The solution for y^'=e^{2x-1}*y^2 is y=-2/(e^{2x-1)+c_{1}}