What is (\partial)/(\partial y)(-xy) ?

The answer to (\partial)/(\partial y)(-xy) is -x

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(\partial)/(\partial y)(-xy)

\frac{\partial}{\partial y} (- x y)

- x

Solution steps

\frac{\partial}{\partial y} (- x y)

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - x \frac{\partial}{\partial y} (y)

Apply the common derivative:

\frac{\partial}{\partial y} (y) = 1

= - x \cdot 1

Simplify

= - x

\frac{d}{d x} ((2 x^{2} + 1)^{4})

\frac{d ^{2}}{d x ^{2}} (e^{- x})

y^{^{'}} = e^{2 x - 1} \cdot y^{2}

\int_{0}^{2} 2 x^{2} d x

\frac{d}{d x} (1 - 2 x^{2})

What is (\partial)/(\partial y)(-xy) ?
The answer to (\partial)/(\partial y)(-xy) is -x