What is the derivative of f(x)= x/(x^2+6) ?

The derivative of f(x)= x/(x^2+6) is (-x^2+6)/((x^2+6)^2)

What is the first derivative of f(x)= x/(x^2+6) ?

The first derivative of f(x)= x/(x^2+6) is (-x^2+6)/((x^2+6)^2)

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derivative of

f (x) = \frac{x}{x ^{2} + 6}

\frac{- x ^{2} + 6}{( x ^{2} + 6 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x}{x ^{2} + 6})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d x}{d x} ( x ^{2} + 6 ) - \frac{d}{d x} ( x ^{2} + 6 ) x}{( x ^{2} + 6 ) ^{2}}

\frac{d x}{d x} = 1

\frac{d}{d x} (x^{2} + 6) = 2 x

= \frac{1 \cdot ( x ^{2} + 6 ) - 2 xx}{( x ^{2} + 6 ) ^{2}}

1 \cdot (x^{2} + 6) - 2 xx = - x^{2} + 6

= \frac{- x ^{2} + 6}{( x ^{2} + 6 ) ^{2}}

x \to 2 lim (5 x^{3} - 9 x^{2} + 1)

x \to \infty lim (4^{x} x)

\frac{3 s ^{2}}{( s ^{2} + 1 ) ^{2}}

\int y \cdot e^{x \cdot y} d x

\int \frac{1}{( x + 5 ) ^{2}} d x

What is the derivative of f(x)= x/(x^2+6) ?
The derivative of f(x)= x/(x^2+6) is (-x^2+6)/((x^2+6)^2)
What is the first derivative of f(x)= x/(x^2+6) ?
The first derivative of f(x)= x/(x^2+6) is (-x^2+6)/((x^2+6)^2)