What is the tangent of f(x)= 3/(x-2),\at x=3 ?

The tangent of f(x)= 3/(x-2),\at x=3 is y=-3x+12

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tangent of f(x)= 3/(x-2),\at x=3

tangent of

f (x) = \frac{3}{x - 2}, at x = 3

y = - 3 x + 12

Solution steps

Find the tangent point:

(3, 3)

Find the slope of

f (x) = \frac{3}{x - 2} : \frac{df ( x )}{d x} = - \frac{3}{( x - 2 ) ^{2}}

Compute the slope of

f (x) = \frac{3}{x - 2}

x = 3 : m = - 3

Find the line with slope m=

- 3

and passing through

(3, 3) : y = - 3 x + 12

y = - 3 x + 12

\int_{0}^{4} \frac{3 t}{( t - 5 ) ^{2}} d t

f (x) = \frac{x}{x ^{2} + 6}

x \to 2 lim (5 x^{3} - 9 x^{2} + 1)

x \to \infty lim (4^{x} x)

\frac{3 s ^{2}}{( s ^{2} + 1 ) ^{2}}

What is the tangent of f(x)= 3/(x-2),\at x=3 ?
The tangent of f(x)= 3/(x-2),\at x=3 is y=-3x+12