derivative of (x^3/3+(x^2)/2-2x+7)

Lösung

\frac{d}{d x} (\frac{x ^{3}}{3} + \frac{x ^{2}}{2} - 2 x + 7)

x^{2} + x - 2

Schritte zur Lösung

\frac{d}{d x} (\frac{x ^{3}}{3} + \frac{x ^{2}}{2} - 2 x + 7)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{x ^{3}}{3}) + \frac{d}{d x} (\frac{x ^{2}}{2}) - \frac{d}{d x} (2 x) + \frac{d}{d x} (7)

\frac{d}{d x} (\frac{x ^{3}}{3}) = x^{2}

\frac{d}{d x} (\frac{x ^{2}}{2}) = x

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (7) = 0

= x^{2} + x - 2 + 0

Vereinfache

= x^{2} + x - 2

(sec (x)) \frac{d y}{d x} + y = 2

\int e^{1 x} d x

in v erse l a pl a ce \frac{e ^{- s}}{s ^{1}}

t an g e n t f (x) = cos (3 x) ln (x^{4}), (1, 0)

\frac{d}{d x} (\frac{9 x ^{2}}{( x ^{2} + x ) ^{3}})