What is the derivative of (9x^2/((x^2+x)^3)) ?

The derivative of (9x^2/((x^2+x)^3)) is (9(-4x-1))/(x^2(x+1)^4)

What is the first derivative of (9x^2/((x^2+x)^3)) ?

The first derivative of (9x^2/((x^2+x)^3)) is (9(-4x-1))/(x^2(x+1)^4)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (\frac{9 x ^{2}}{( x ^{2} + x ) ^{3}})

\frac{9 ( - 4 x - 1 )}{x ^{2} ( x + 1 ) ^{4}}

Solution steps

\frac{d}{d x} (\frac{9 x ^{2}}{( x ^{2} + x ) ^{3}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 9 \frac{d}{d x} (\frac{x ^{2}}{( x ^{2} + x ) ^{3}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= 9 \cdot \frac{\frac{d}{d x} ( x ^{2} ) ( x ^{2} + x ) ^{3} - \frac{d}{d x} ( ( x ^{2} + x ) ^{3} ) x ^{2}}{( ( x ^{2} + x ) ^{3} ) ^{2}}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} ((x^{2} + x)^{3}) = 3 (x^{2} + x)^{2} (2 x + 1)

= 9 \cdot \frac{2 x ( x ^{2} + x ) ^{3} - 3 ( x ^{2} + x ) ^{2} ( 2 x + 1 ) x ^{2}}{( ( x ^{2} + x ) ^{3} ) ^{2}}

Simplify

9 \cdot \frac{2 x ( x ^{2} + x ) ^{3} - 3 ( x ^{2} + x ) ^{2} ( 2 x + 1 ) x ^{2}}{( ( x ^{2} + x ) ^{3} ) ^{2}} : \frac{9 ( - 4 x - 1 )}{x ^{2} ( x + 1 ) ^{4}}

= \frac{9 ( - 4 x - 1 )}{x ^{2} ( x + 1 ) ^{4}}

\int \frac{4 - x ^{2}}{x ^{4}} d x

ln (ln (8 x))

\frac{- x ^{3}}{y ^{3}}

y = 4 x, y = 2 x^{2}

14 x^{3} + 7 x^{2} + 11 x - 29

What is the derivative of (9x^2/((x^2+x)^3)) ?
The derivative of (9x^2/((x^2+x)^3)) is (9(-4x-1))/(x^2(x+1)^4)
What is the first derivative of (9x^2/((x^2+x)^3)) ?
The first derivative of (9x^2/((x^2+x)^3)) is (9(-4x-1))/(x^2(x+1)^4)