What is the tangent of f(x)=cos(3x)ln(x^4),(1,0) ?

The tangent of f(x)=cos(3x)ln(x^4),(1,0) is y=4cos(3)x-4cos(3)

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tangent of f(x)=cos(3x)ln(x^4),(1,0)

tangent of

f (x) = cos (3 x) ln (x^{4}), (1, 0)

y = 4 cos (3) x - 4 cos (3)

Solution steps

Find the slope of

f (x) = cos (3 x) ln (x^{4}) : \frac{df ( x )}{d x} = - 3 sin (3 x) ln (x^{4}) + \frac{4 cos ( 3 x )}{x}

Compute the slope of

f (x) = cos (3 x) ln (x^{4})

(1, 0) : m = 4 cos (3)

Find the line with slope m=

4 cos (3)

and passing through

(1, 0) : y = 4 cos (3) x - 4 cos (3)

y = 4 cos (3) x - 4 cos (3)

\frac{d}{d x} (\frac{9 x ^{2}}{( x ^{2} + x ) ^{3}})

\int \frac{4 - x ^{2}}{x ^{4}} d x

ln (ln (8 x))

\frac{- x ^{3}}{y ^{3}}

y = 4 x, y = 2 x^{2}

What is the tangent of f(x)=cos(3x)ln(x^4),(1,0) ?
The tangent of f(x)=cos(3x)ln(x^4),(1,0) is y=4cos(3)x-4cos(3)