What is the derivative of 0.5cos(2pit) ?

The derivative of 0.5cos(2pit) is -3.14159…sin(6.28318…t)

What is the first derivative of 0.5cos(2pit) ?

The first derivative of 0.5cos(2pit) is -3.14159…sin(6.28318…t)

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derivative of

0.5 cos (2 π t)

- 3.14159 \dots sin (6.28318 \dots t)

Solution steps

\frac{d}{d t} (0.5 cos (2 π t))

Simplify

0.5 cos (2 π t) : 0.5 cos (6.28318 \dots t)

= \frac{d}{d t} (0.5 cos (6.28318 \dots t))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 0.5 \frac{d}{d t} (cos (6.28318 \dots t))

Apply the chain rule:

- sin (6.28318 \dots t) \frac{d}{d t} (6.28318 \dots t)

= - sin (6.28318 \dots t) \frac{d}{d t} (6.28318 \dots t)

\frac{d}{d t} (6.28318 \dots t) = 6.28318 \dots

= 0.5 (- sin (6.28318 \dots t) \cdot 6.28318 \dots)

Simplify

= - 3.14159 \dots sin (6.28318 \dots t)

\frac{\partial}{\partial x} (4 x y^{3} + 1)

f (x) = \frac{1}{x} - ln (x)

n = 1 \sum \infty \frac{7 ^{n}}{n !}

f (x) = π (10 - \frac{π}{3}) x^{2}, at x = 3

\frac{d}{d x} (\frac{18}{x ^{3}})

What is the derivative of 0.5cos(2pit) ?
The derivative of 0.5cos(2pit) is -3.14159…sin(6.28318…t)
What is the first derivative of 0.5cos(2pit) ?
The first derivative of 0.5cos(2pit) is -3.14159…sin(6.28318…t)