What is the tangent of f(x)=pi(10-pi/3)x^2,\at x=3 ?

The tangent of f(x)=pi(10-pi/3)x^2,\at x=3 is y=6pi(10-pi/3)x-9pi(10-pi/3)

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tangent of f(x)=pi(10-pi/3)x^2,\at x=3

tangent of

f (x) = π (10 - \frac{π}{3}) x^{2}, at x = 3

y = 6 π (10 - \frac{π}{3}) x - 9 π (10 - \frac{π}{3})

Solution steps

Find the tangent point:

(3, 9 π (10 - \frac{π}{3}))

Find the slope of

f (x) = π (10 - \frac{π}{3}) x^{2} : \frac{df ( x )}{d x} = 2 π (10 - \frac{π}{3}) x

Compute the slope of

f (x) = π (10 - \frac{π}{3}) x^{2}

x = 3 : m = 6 π (10 - \frac{π}{3})

Find the line with slope m=

6 π (10 - \frac{π}{3})

and passing through

(3, 9 π (10 - \frac{π}{3})) : y = 6 π (10 - \frac{π}{3}) x - 9 π (10 - \frac{π}{3})

y = 6 π (10 - \frac{π}{3}) x - 9 π (10 - \frac{π}{3})

\frac{d}{d x} (\frac{18}{x ^{3}})

x \to 0 + lim (x \cdot ln (x))

\int_{1}^{12} 8 x^{- 2} d x

\frac{d}{d x} (\frac{3 + csc ( x )}{7 - csc ( x )})

y^{^{'}} = y + 1 + 2 sin (t)

What is the tangent of f(x)=pi(10-pi/3)x^2,\at x=3 ?
The tangent of f(x)=pi(10-pi/3)x^2,\at x=3 is y=6pi(10-pi/3)x-9pi(10-pi/3)