What is the integral from 1 to 12 of 8x^{-2} ?

The integral from 1 to 12 of 8x^{-2} is 22/3

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integral from 1 to 12 of 8x^{-2}

\int_{1}^{12} 8 x^{- 2} d x

\frac{22}{3}

Decimal Notation

7.33333 \dots

Solution steps

\int_{1}^{12} 8 x^{- 2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 8 \cdot \int_{1}^{12} x^{- 2} d x

Apply the Power Rule

: [- \frac{1}{x}]_{1}^{12}

= 8 [- \frac{1}{x}]_{1}^{12}

Compute the boundaries:

\frac{11}{12}

= 8 \cdot \frac{11}{12}

Simplify

= \frac{22}{3}

\frac{d}{d x} (\frac{3 + csc ( x )}{7 - csc ( x )})

y^{^{'}} = y + 1 + 2 sin (t)

x \to 0 + lim (\frac{2 x}{ln ( x )})

\int \frac{cos ( x )}{cos ( x )} d x

8 x^{2} + x y + 8 y^{2} = 17, (1, 1)

What is the integral from 1 to 12 of 8x^{-2} ?
The integral from 1 to 12 of 8x^{-2} is 22/3