What is (\partial)/(\partial x)(4xy^3+1) ?

The answer to (\partial)/(\partial x)(4xy^3+1) is 4y^3

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(\partial)/(\partial x)(4xy^3+1)

\frac{\partial}{\partial x} (4 x y^{3} + 1)

4 y^{3}

Solution steps

\frac{\partial}{\partial x} (4 x y^{3} + 1)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (4 x y^{3}) + \frac{\partial}{\partial x} (1)

\frac{\partial}{\partial x} (4 x y^{3}) = 4 y^{3}

\frac{\partial}{\partial x} (1) = 0

= 4 y^{3} + 0

Simplify

= 4 y^{3}

f (x) = \frac{1}{x} - ln (x)

n = 1 \sum \infty \frac{7 ^{n}}{n !}

f (x) = π (10 - \frac{π}{3}) x^{2}, at x = 3

\frac{d}{d x} (\frac{18}{x ^{3}})

x \to 0 + lim (x \cdot ln (x))

What is (\partial)/(\partial x)(4xy^3+1) ?
The answer to (\partial)/(\partial x)(4xy^3+1) is 4y^3