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Popular >

y^'+2y=3,y(0)=0

Solution

y^{^{'}} + 2 y = 3, y (0) = 0

Solution

y = - \frac{3 e ^{- 2 t}}{2} + \frac{3}{2}

Solution steps

y^{'} (t) + 2 y = 3

Solve separable ODE:

y = - \frac{3 e ^{- 2 t}}{2} + \frac{3}{2}

y = - \frac{3 e ^{- 2 t}}{2} + \frac{3}{2}

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Frequently Asked Questions (FAQ)

What is the solution for y^'+2y=3,y(0)=0 ?
The solution for y^'+2y=3,y(0)=0 is y=-(3e^{-2t})/2+3/2