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Popular >

(\partial)/(\partial x)(xy-x-y+1)

Solution

\frac{\partial}{\partial x} (x y - x - y + 1)

Solution

y - 1

Solution steps

\frac{\partial}{\partial x} (x y - x - y + 1)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x y) - \frac{\partial}{\partial x} (x) - \frac{\partial}{\partial x} (y) + \frac{\partial}{\partial x} (1)

\frac{\partial}{\partial x} (x y) = y

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (y) = 0

\frac{\partial}{\partial x} (1) = 0

= y - 1 - 0 + 0

Simplify

= y - 1

Popular Examples

integral of 1/(y^2-y+1)

\int \frac{1}{y ^{2} - y + 1} d y

integral from 0 to 1 of 7^{2x}

\int_{0}^{1} 7^{2 x} d x

limit as x approaches 0 of (cos(3x)tan(3x))/x

x \to 0 lim (\frac{cos ( 3 x ) tan ( 3 x )}{x})

y^{^{'}} = y - 2 x

integral of (4x^3)/(1+x^4)

\int \frac{4 x ^{3}}{1 + x ^{4}} d x

Frequently Asked Questions (FAQ)

What is (\partial)/(\partial x)(xy-x-y+1) ?
The answer to (\partial)/(\partial x)(xy-x-y+1) is y-1