What is the integral from 0 to 1 of \sqrt[3]{x}-x^2 ?

The integral from 0 to 1 of \sqrt[3]{x}-x^2 is 5/12

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integral from 0 to 1 of \sqrt[3]{x}-x^2

\frac{5}{12}

Decimal Notation

0.41666 \dots

Solution steps

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

\int_{0}^{1} x^{2} d x = \frac{1}{3}

= \frac{3}{4} - \frac{1}{3}

Simplify

\frac{3}{4} - \frac{1}{3} : \frac{5}{12}

= \frac{5}{12}

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x \to 0 lim (\frac{cos ( 3 x ) tan ( 3 x )}{x})

What is the integral from 0 to 1 of \sqrt[3]{x}-x^2 ?
The integral from 0 to 1 of \sqrt[3]{x}-x^2 is 5/12