What is the derivative of 2ln(x)+6 ?

The derivative of 2ln(x)+6 is 2/x

What is the first derivative of 2ln(x)+6 ?

The first derivative of 2ln(x)+6 is 2/x

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derivative of

2 ln (x) + 6

\frac{2}{x}

Solution steps

\frac{d}{d x} (2 ln (x) + 6)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 ln (x)) + \frac{d}{d x} (6)

\frac{d}{d x} (2 ln (x)) = \frac{2}{x}

\frac{d}{d x} (6) = 0

= \frac{2}{x} + 0

Simplify

= \frac{2}{x}

\frac{\partial}{\partial x} (x y - x - y + 1)

\int \frac{1}{y ^{2} - y + 1} d y

\int_{0}^{1} 7^{2 x} d x

x \to 0 lim (\frac{cos ( 3 x ) tan ( 3 x )}{x})

y^{^{'}} = y - 2 x

What is the derivative of 2ln(x)+6 ?
The derivative of 2ln(x)+6 is 2/x
What is the first derivative of 2ln(x)+6 ?
The first derivative of 2ln(x)+6 is 2/x