3^{2x-1}=17

Lösung

3^{2 x - 1} = 17

x = \frac{ln ( 51 )}{2 ln ( 3 )}

Dezimale

x = 1.78945 \dots

Schritte zur Lösung

3^{2 x - 1} = 17

Wende Exponentenregel an

(2 x - 1) ln (3) = ln (17)

Löse

(2 x - 1) ln (3) = ln (17) : x = \frac{ln ( 51 )}{2 ln ( 3 )}

x = \frac{ln ( 51 )}{2 ln ( 3 )}

so l v e f or x, e^{7 - 4 x} = 6

2^{3 x + 5} = 6 4^{x - 7}

e^{2 x} - 8 e^{x} + 15 = 0

200 = 100 e^{r \cdot 6}

2^{x} = 24