What is the general solution for 3cos(x)+2sin^2(x)=0 ?

The general solution for 3cos(x)+2sin^2(x)=0 is x=(2pi)/3+2pin,x=(4pi)/3+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3cos(x)+2sin^2(x)=0

3 cos (x) + 2 sin^{2} (x) = 0

x = \frac{2 π}{3} + 2 πn, x = \frac{4 π}{3} + 2 πn

Solution steps

3 cos (x) + 2 sin^{2} (x) = 0

Rewrite using trig identities

(1 - cos^{2} (x)) \cdot 2 + 3 cos (x) = 0

Solve by substitution

cos (x) = - \frac{1}{2}, cos (x) = 2

cos (x) = - \frac{1}{2} : x = \frac{2 π}{3} + 2 πn, x = \frac{4 π}{3} + 2 πn

cos (x) = 2 :

No Solution

Combine all the solutions

x = \frac{2 π}{3} + 2 πn, x = \frac{4 π}{3} + 2 πn

tan (\frac{3 π}{8})

7 sin (2 X) = 0

sec (- \frac{π}{6})

sin (x) (tan (x)) = sec (x) - cos (x)

cos (θ) = 0

What is the general solution for 3cos(x)+2sin^2(x)=0 ?
The general solution for 3cos(x)+2sin^2(x)=0 is x=(2pi)/3+2pin,x=(4pi)/3+2pin