What is the general solution for sin(t)=-0.9397 ?

The general solution for sin(t)=-0.9397 is t=-1.22175…+2pin,t=pi+1.22175…+2pin

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sin(t)=-0.9397

sin (t) = - 0.9397

t = - 1.22175 \dots + 2 πn, t = π + 1.22175 \dots + 2 πn

Solution steps

sin (t) = - 0.9397

Apply trig inverse properties

t = arcsin (- 0.9397) + 2 πn, t = π + arcsin (0.9397) + 2 πn

Show solutions in decimal form

t = - 1.22175 \dots + 2 πn, t = π + 1.22175 \dots + 2 πn

tan^{2} (x) = 2 sec^{2} (x) - 3

sinh (x) + 4 = 4 cosh (x)

sin (18 x) = - 1

x, y + sin (x y) = 1

(sec^{2} (+ 1)) (sec^{2} (- 1)) = tan (x)

What is the general solution for sin(t)=-0.9397 ?
The general solution for sin(t)=-0.9397 is t=-1.22175…+2pin,t=pi+1.22175…+2pin