What is the general solution for sinh(x)+4=4cosh(x) ?

The general solution for sinh(x)+4=4cosh(x) is x=0,x=ln(5/3)

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sinh(x)+4=4cosh(x)

sinh (x) + 4 = 4 cosh (x)

x = 0, x = ln (\frac{5}{3})

Solution steps

sinh (x) + 4 = 4 cosh (x)

Rewrite using trig identities

\frac{e ^{x} - e ^{- x}}{2} + 4 = 4 \cdot \frac{e ^{x} + e ^{- x}}{2}

\frac{e ^{x} - e ^{- x}}{2} + 4 = 4 \cdot \frac{e ^{x} + e ^{- x}}{2} : x = 0, x = ln (\frac{5}{3})

x = 0, x = ln (\frac{5}{3})

sin (18 x) = - 1

x, y + sin (x y) = 1

(sec^{2} (+ 1)) (sec^{2} (- 1)) = tan (x)

2 cos^{2} (x) - 8 cos (x) = 2 sin^{2} (x) - 5

2 cos^{2} (a) tan (a) = tan (a)

What is the general solution for sinh(x)+4=4cosh(x) ?
The general solution for sinh(x)+4=4cosh(x) is x=0,x=ln(5/3)