What is the general solution for sin(18x)=-1 ?

The general solution for sin(18x)=-1 is x= pi/(12)+(pin)/9

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sin(18x)=-1

sin (18 x) = - 1

x = \frac{π}{12} + \frac{πn}{9}

Solution steps

sin (18 x) = - 1

General solutions for

sin (18 x) = - 1

18 x = \frac{3 π}{2} + 2 πn

Solve

18 x = \frac{3 π}{2} + 2 πn : x = \frac{π}{12} + \frac{πn}{9}

x = \frac{π}{12} + \frac{πn}{9}

x, y + sin (x y) = 1

(sec^{2} (+ 1)) (sec^{2} (- 1)) = tan (x)

2 cos^{2} (x) - 8 cos (x) = 2 sin^{2} (x) - 5

2 cos^{2} (a) tan (a) = tan (a)

sin^{2} (x) + 5 sin (x) + 5 = 0

What is the general solution for sin(18x)=-1 ?
The general solution for sin(18x)=-1 is x= pi/(12)+(pin)/9