What is the general solution for sin^2(x)+5sin(x)+5=0 ?

The general solution for sin^2(x)+5sin(x)+5=0 is No Solution for x\in\mathbb{R}

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sin^2(x)+5sin(x)+5=0

sin^{2} (x) + 5 sin (x) + 5 = 0

No Solution for x \in R

Solution steps

sin^{2} (x) + 5 sin (x) + 5 = 0

Solve by substitution

sin (x) = \frac{- 5 + 5}{2}, sin (x) = \frac{- 5 - 5}{2}

sin (x) = \frac{- 5 + 5}{2} :

No Solution

sin (x) = \frac{- 5 - 5}{2} :

No Solution

Combine all the solutions

No Solution for x \in R

cos (x) = - 0.814

3 cos^{2} (x) - 8 cos (x) + 4 = sin^{2} (x)

cos (x - 4 5^{\circ}) = \frac{- 1}{2}

x, sin (x + \frac{r}{4}) + sin (x - \frac{r}{3}) = 0

cos^{2} (x) = 2 sin^{2} (x)

What is the general solution for sin^2(x)+5sin(x)+5=0 ?
The general solution for sin^2(x)+5sin(x)+5=0 is No Solution for x\in\mathbb{R}