{
"query": {
"display": "$$\\sin^{3}\\left(x\\right)=\\sin^{2}\\left(x\\right)$$",
"symbolab_question": "EQUATION#\\sin^{3}(x)=\\sin^{2}(x)"
},
"solution": {
"level": "PERFORMED",
"subject": "Trigonometry",
"topic": "Trig Equations",
"subTopic": "Trig Equations",
"default": "x=2πn,x=π+2πn,x=\\frac{π}{2}+2πn",
"degrees": "x=0^{\\circ }+360^{\\circ }n,x=180^{\\circ }+360^{\\circ }n,x=90^{\\circ }+360^{\\circ }n",
"meta": {
"showVerify": true
}
},
"steps": {
"type": "interim",
"title": "$$\\sin^{3}\\left(x\\right)=\\sin^{2}\\left(x\\right){\\quad:\\quad}x=2πn,\\:x=π+2πn,\\:x=\\frac{π}{2}+2πn$$",
"input": "\\sin^{3}\\left(x\\right)=\\sin^{2}\\left(x\\right)",
"steps": [
{
"type": "interim",
"title": "Solve by substitution",
"input": "\\sin^{3}\\left(x\\right)=\\sin^{2}\\left(x\\right)",
"result": "\\sin\\left(x\\right)=0,\\:\\sin\\left(x\\right)=1",
"steps": [
{
"type": "step",
"primary": "Let: $$\\sin\\left(x\\right)=u$$",
"result": "u^{3}=u^{2}"
},
{
"type": "interim",
"title": "$$u^{3}=u^{2}{\\quad:\\quad}u=0,\\:u=1$$",
"input": "u^{3}=u^{2}",
"steps": [
{
"type": "interim",
"title": "Move $$u^{2}\\:$$to the left side",
"input": "u^{3}=u^{2}",
"result": "u^{3}-u^{2}=0",
"steps": [
{
"type": "step",
"primary": "Subtract $$u^{2}$$ from both sides",
"result": "u^{3}-u^{2}=u^{2}-u^{2}"
},
{
"type": "step",
"primary": "Simplify",
"result": "u^{3}-u^{2}=0"
}
],
"meta": {
"interimType": "Move to the Left Title 1Eq",
"gptData": "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"
}
},
{
"type": "interim",
"title": "Factor $$u^{3}-u^{2}:{\\quad}u^{2}\\left(u-1\\right)$$",
"input": "u^{3}-u^{2}",
"steps": [
{
"type": "step",
"primary": "Apply exponent rule: $$a^{b+c}=a^{b}a^{c}$$",
"secondary": [
"$$u^{3}=uu^{2}$$"
],
"result": "=uu^{2}-u^{2}",
"meta": {
"practiceLink": "/practice/exponent-practice",
"practiceTopic": "Expand FOIL"
}
},
{
"type": "step",
"primary": "Factor out common term $$u^{2}$$",
"result": "=u^{2}\\left(u-1\\right)",
"meta": {
"practiceLink": "/practice/factoring-practice",
"practiceTopic": "Factoring"
}
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Generic Factor Specific 1Eq"
}
},
{
"type": "step",
"result": "u^{2}\\left(u-1\\right)=0"
},
{
"type": "step",
"primary": "Using the Zero Factor Principle:$$\\quad$$ If $$ab=0\\:$$then $$a=0\\:$$or $$b=0$$",
"result": "u=0\\lor\\:u-1=0"
},
{
"type": "interim",
"title": "Solve $$u-1=0:{\\quad}u=1$$",
"input": "u-1=0",
"steps": [
{
"type": "interim",
"title": "Move $$1\\:$$to the right side",
"input": "u-1=0",
"result": "u=1",
"steps": [
{
"type": "step",
"primary": "Add $$1$$ to both sides",
"result": "u-1+1=0+1"
},
{
"type": "step",
"primary": "Simplify",
"result": "u=1"
}
],
"meta": {
"interimType": "Move to the Right Title 1Eq",
"gptData": "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"
}
}
],
"meta": {
"solvingClass": "Equations",
"interimType": "Generic Solve Title 1Eq"
}
},
{
"type": "step",
"primary": "The solutions are",
"result": "u=0,\\:u=1"
}
],
"meta": {
"solvingClass": "Equations",
"interimType": "Equations"
}
},
{
"type": "step",
"primary": "Substitute back $$u=\\sin\\left(x\\right)$$",
"result": "\\sin\\left(x\\right)=0,\\:\\sin\\left(x\\right)=1"
}
],
"meta": {
"interimType": "Substitution Method 0Eq"
}
},
{
"type": "interim",
"title": "$$\\sin\\left(x\\right)=0{\\quad:\\quad}x=2πn,\\:x=π+2πn$$",
"input": "\\sin\\left(x\\right)=0",
"steps": [
{
"type": "interim",
"title": "General solutions for $$\\sin\\left(x\\right)=0$$",
"result": "x=0+2πn,\\:x=π+2πn",
"steps": [
{
"type": "step",
"primary": "$$\\sin\\left(x\\right)$$ periodicity table with $$2πn$$ cycle:<br/>$$\\begin{array}{|c|c|c|c|}\\hline x&\\sin(x)&x&\\sin(x)\\\\\\hline 0&0&π&0\\\\\\hline \\frac{π}{6}&\\frac{1}{2}&\\frac{7π}{6}&-\\frac{1}{2}\\\\\\hline \\frac{π}{4}&\\frac{\\sqrt{2}}{2}&\\frac{5π}{4}&-\\frac{\\sqrt{2}}{2}\\\\\\hline \\frac{π}{3}&\\frac{\\sqrt{3}}{2}&\\frac{4π}{3}&-\\frac{\\sqrt{3}}{2}\\\\\\hline \\frac{π}{2}&1&\\frac{3π}{2}&-1\\\\\\hline \\frac{2π}{3}&\\frac{\\sqrt{3}}{2}&\\frac{5π}{3}&-\\frac{\\sqrt{3}}{2}\\\\\\hline \\frac{3π}{4}&\\frac{\\sqrt{2}}{2}&\\frac{7π}{4}&-\\frac{\\sqrt{2}}{2}\\\\\\hline \\frac{5π}{6}&\\frac{1}{2}&\\frac{11π}{6}&-\\frac{1}{2}\\\\\\hline \\end{array}$$"
},
{
"type": "step",
"result": "x=0+2πn,\\:x=π+2πn"
}
],
"meta": {
"interimType": "Trig General Solutions sin 1Eq"
}
},
{
"type": "interim",
"title": "Solve $$x=0+2πn:{\\quad}x=2πn$$",
"input": "x=0+2πn",
"steps": [
{
"type": "step",
"primary": "$$0+2πn=2πn$$",
"result": "x=2πn"
}
],
"meta": {
"solvingClass": "Equations",
"interimType": "Generic Solve Title 1Eq"
}
},
{
"type": "step",
"result": "x=2πn,\\:x=π+2πn"
}
],
"meta": {
"interimType": "N/A"
}
},
{
"type": "interim",
"title": "$$\\sin\\left(x\\right)=1{\\quad:\\quad}x=\\frac{π}{2}+2πn$$",
"input": "\\sin\\left(x\\right)=1",
"steps": [
{
"type": "interim",
"title": "General solutions for $$\\sin\\left(x\\right)=1$$",
"result": "x=\\frac{π}{2}+2πn",
"steps": [
{
"type": "step",
"primary": "$$\\sin\\left(x\\right)$$ periodicity table with $$2πn$$ cycle:<br/>$$\\begin{array}{|c|c|c|c|}\\hline x&\\sin(x)&x&\\sin(x)\\\\\\hline 0&0&π&0\\\\\\hline \\frac{π}{6}&\\frac{1}{2}&\\frac{7π}{6}&-\\frac{1}{2}\\\\\\hline \\frac{π}{4}&\\frac{\\sqrt{2}}{2}&\\frac{5π}{4}&-\\frac{\\sqrt{2}}{2}\\\\\\hline \\frac{π}{3}&\\frac{\\sqrt{3}}{2}&\\frac{4π}{3}&-\\frac{\\sqrt{3}}{2}\\\\\\hline \\frac{π}{2}&1&\\frac{3π}{2}&-1\\\\\\hline \\frac{2π}{3}&\\frac{\\sqrt{3}}{2}&\\frac{5π}{3}&-\\frac{\\sqrt{3}}{2}\\\\\\hline \\frac{3π}{4}&\\frac{\\sqrt{2}}{2}&\\frac{7π}{4}&-\\frac{\\sqrt{2}}{2}\\\\\\hline \\frac{5π}{6}&\\frac{1}{2}&\\frac{11π}{6}&-\\frac{1}{2}\\\\\\hline \\end{array}$$"
},
{
"type": "step",
"result": "x=\\frac{π}{2}+2πn"
}
],
"meta": {
"interimType": "Trig General Solutions sin 1Eq"
}
}
],
"meta": {
"interimType": "N/A"
}
},
{
"type": "step",
"primary": "Combine all the solutions",
"result": "x=2πn,\\:x=π+2πn,\\:x=\\frac{π}{2}+2πn"
}
],
"meta": {
"solvingClass": "Trig Equations",
"practiceLink": "/practice/trigonometry-practice#area=main&subtopic=Trig%20Equations",
"practiceTopic": "Trig Equations"
}
},
"plot_output": {
"meta": {
"plotInfo": {
"variable": "x",
"plotRequest": "\\sin^{3}(x)-\\sin^{2}(x)"
},
"showViewLarger": true
}
},
"meta": {
"showVerify": true
}
}
Solution
Solution
+1
Degrees
Solution steps
Solve by substitution
Let:
Move to the left side
Subtract from both sides
Simplify
Factor
Apply exponent rule:
Factor out common term
Using the Zero Factor Principle: If then or
Solve
Move to the right side
Add to both sides
Simplify
The solutions are
Substitute back
General solutions for
periodicity table with cycle:
Solve
General solutions for
periodicity table with cycle:
Combine all the solutions
Graph
Popular Examples
2sec^2(a)+tan^2(a)=33cos^2(x)+4cos(x)+1=0cos^5(x)= 1/2(cos^{2022}(x))/((sin^{2022)(x)+cos^{2022}(x))}=15sec(x)-4cos(x)=8
Frequently Asked Questions (FAQ)
What is the general solution for sin^3(x)=sin^2(x) ?
The general solution for sin^3(x)=sin^2(x) is x=2pin,x=pi+2pin,x= pi/2+2pin