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Popular Trigonometry >

5sec(x)-4cos(x)=8

  • Pre Algebra
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Solution

5sec(x)−4cos(x)=8

Solution

x=3π​+2πn,x=35π​+2πn
+1
Degrees
x=60∘+360∘n,x=300∘+360∘n
Solution steps
5sec(x)−4cos(x)=8
Subtract 8 from both sides5sec(x)−4cos(x)−8=0
Rewrite using trig identities
−8−4cos(x)+5sec(x)
Use the basic trigonometric identity: cos(x)=sec(x)1​=−8−4⋅sec(x)1​+5sec(x)
4⋅sec(x)1​=sec(x)4​
4⋅sec(x)1​
Multiply fractions: a⋅cb​=ca⋅b​=sec(x)1⋅4​
Multiply the numbers: 1⋅4=4=sec(x)4​
=−8−sec(x)4​+5sec(x)
−8−sec(x)4​+5sec(x)=0
Solve by substitution
−8−sec(x)4​+5sec(x)=0
Let: sec(x)=u−8−u4​+5u=0
−8−u4​+5u=0:u=2,u=−52​
−8−u4​+5u=0
Multiply both sides by u
−8−u4​+5u=0
Multiply both sides by u−8u−u4​u+5uu=0⋅u
Simplify
−8u−u4​u+5uu=0⋅u
Simplify −u4​u:−4
−u4​u
Multiply fractions: a⋅cb​=ca⋅b​=−u4u​
Cancel the common factor: u=−4
Simplify 5uu:5u2
5uu
Apply exponent rule: ab⋅ac=ab+cuu=u1+1=5u1+1
Add the numbers: 1+1=2=5u2
Simplify 0⋅u:0
0⋅u
Apply rule 0⋅a=0=0
−8u−4+5u2=0
−8u−4+5u2=0
−8u−4+5u2=0
Solve −8u−4+5u2=0:u=2,u=−52​
−8u−4+5u2=0
Write in the standard form ax2+bx+c=05u2−8u−4=0
Solve with the quadratic formula
5u2−8u−4=0
Quadratic Equation Formula:
For a=5,b=−8,c=−4u1,2​=2⋅5−(−8)±(−8)2−4⋅5(−4)​​
u1,2​=2⋅5−(−8)±(−8)2−4⋅5(−4)​​
(−8)2−4⋅5(−4)​=12
(−8)2−4⋅5(−4)​
Apply rule −(−a)=a=(−8)2+4⋅5⋅4​
Apply exponent rule: (−a)n=an,if n is even(−8)2=82=82+4⋅5⋅4​
Multiply the numbers: 4⋅5⋅4=80=82+80​
82=64=64+80​
Add the numbers: 64+80=144=144​
Factor the number: 144=122=122​
Apply radical rule: 122​=12=12
u1,2​=2⋅5−(−8)±12​
Separate the solutionsu1​=2⋅5−(−8)+12​,u2​=2⋅5−(−8)−12​
u=2⋅5−(−8)+12​:2
2⋅5−(−8)+12​
Apply rule −(−a)=a=2⋅58+12​
Add the numbers: 8+12=20=2⋅520​
Multiply the numbers: 2⋅5=10=1020​
Divide the numbers: 1020​=2=2
u=2⋅5−(−8)−12​:−52​
2⋅5−(−8)−12​
Apply rule −(−a)=a=2⋅58−12​
Subtract the numbers: 8−12=−4=2⋅5−4​
Multiply the numbers: 2⋅5=10=10−4​
Apply the fraction rule: b−a​=−ba​=−104​
Cancel the common factor: 2=−52​
The solutions to the quadratic equation are:u=2,u=−52​
u=2,u=−52​
Verify Solutions
Find undefined (singularity) points:u=0
Take the denominator(s) of −8−u4​+5u and compare to zero
u=0
The following points are undefinedu=0
Combine undefined points with solutions:
u=2,u=−52​
Substitute back u=sec(x)sec(x)=2,sec(x)=−52​
sec(x)=2,sec(x)=−52​
sec(x)=2:x=3π​+2πn,x=35π​+2πn
sec(x)=2
General solutions for sec(x)=2
sec(x) periodicity table with 2πn cycle:
x06π​4π​3π​2π​32π​43π​65π​​sec(x)1323​​2​2Undefined−2−2​−323​​​xπ67π​45π​34π​23π​35π​47π​611π​​sec(x)−1−323​​−2​−2Undefined22​323​​​​
x=3π​+2πn,x=35π​+2πn
x=3π​+2πn,x=35π​+2πn
sec(x)=−52​:No Solution
sec(x)=−52​
sec(x)≤−1orsec(x)≥1NoSolution
Combine all the solutionsx=3π​+2πn,x=35π​+2πn

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Frequently Asked Questions (FAQ)

  • What is the general solution for 5sec(x)-4cos(x)=8 ?

    The general solution for 5sec(x)-4cos(x)=8 is x= pi/3+2pin,x=(5pi)/3+2pin
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