{
"query": {
"display": "$$\\sin^{3}\\left(x\\right)=-1$$",
"symbolab_question": "EQUATION#\\sin^{3}(x)=-1"
},
"solution": {
"level": "PERFORMED",
"subject": "Trigonometry",
"topic": "Trig Equations",
"subTopic": "Trig Equations",
"default": "x=\\frac{3π}{2}+2πn",
"degrees": "x=270^{\\circ }+360^{\\circ }n",
"meta": {
"showVerify": true
}
},
"steps": {
"type": "interim",
"title": "$$\\sin^{3}\\left(x\\right)=-1{\\quad:\\quad}x=\\frac{3π}{2}+2πn$$",
"input": "\\sin^{3}\\left(x\\right)=-1",
"steps": [
{
"type": "interim",
"title": "Solve by substitution",
"input": "\\sin^{3}\\left(x\\right)=-1",
"result": "\\sin\\left(x\\right)=-1,\\:\\sin\\left(x\\right)=\\frac{1}{2}-i\\frac{\\sqrt{3}}{2},\\:\\sin\\left(x\\right)=\\frac{1}{2}+i\\frac{\\sqrt{3}}{2}",
"steps": [
{
"type": "step",
"primary": "Let: $$\\sin\\left(x\\right)=u$$",
"result": "u^{3}=-1"
},
{
"type": "interim",
"title": "$$u^{3}=-1{\\quad:\\quad}u=-1,\\:u=\\frac{1}{2}-i\\frac{\\sqrt{3}}{2},\\:u=\\frac{1}{2}+i\\frac{\\sqrt{3}}{2}$$",
"input": "u^{3}=-1",
"steps": [
{
"type": "step",
"primary": "For $$x^{3}=f\\left(a\\right)$$ the solutions are $$x=\\sqrt[3]{f\\left(a\\right)},\\:\\sqrt[3]{f\\left(a\\right)}\\frac{-1-\\sqrt{3}i}{2},\\:\\sqrt[3]{f\\left(a\\right)}\\frac{-1+\\sqrt{3}i}{2}$$"
},
{
"type": "step",
"result": "u=\\sqrt[3]{-1},\\:u=\\sqrt[3]{-1}\\frac{-1+\\sqrt{3}i}{2},\\:u=\\sqrt[3]{-1}\\frac{-1-\\sqrt{3}i}{2}"
},
{
"type": "interim",
"title": "$$\\sqrt[3]{-1}=-1$$",
"input": "\\sqrt[3]{-1}",
"steps": [
{
"type": "step",
"primary": "$$\\sqrt[n]{-1}=-1,\\:$$if $$n$$ is odd",
"secondary": [
"$$\\sqrt[3]{-1}=-1$$"
],
"result": "=-1"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Solver",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s76H1xoeptwwOonZRztLDv7i061ljBSPJeENOw2efoSWuixCfF7o9L2hRx9Shm0jmvo3oe/oyhMy2+1TQhDBd2f8qdr6Xp5CVvDj5nIWgDseQkt3WiGR7ZaCaXvz77bMjS"
}
},
{
"type": "interim",
"title": "Simplify $$\\sqrt[3]{-1}\\frac{-1+\\sqrt{3}i}{2}:{\\quad}\\frac{1}{2}-i\\frac{\\sqrt{3}}{2}$$",
"input": "\\sqrt[3]{-1}\\frac{-1+\\sqrt{3}i}{2}",
"steps": [
{
"type": "interim",
"title": "$$\\sqrt[3]{-1}=-1$$",
"input": "\\sqrt[3]{-1}",
"steps": [
{
"type": "step",
"primary": "$$\\sqrt[n]{-1}=-1,\\:$$if $$n$$ is odd",
"secondary": [
"$$\\sqrt[3]{-1}=-1$$"
],
"result": "=-1"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Solver",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s76H1xoeptwwOonZRztLDv7i061ljBSPJeENOw2efoSWuixCfF7o9L2hRx9Shm0jmvo3oe/oyhMy2+1TQhDBd2f8qdr6Xp5CVvDj5nIWgDseQkt3WiGR7ZaCaXvz77bMjS"
}
},
{
"type": "step",
"result": "=-1\\cdot\\:\\frac{-1+\\sqrt{3}i}{2}"
},
{
"type": "step",
"primary": "Multiply: $$1\\cdot\\:\\frac{-1+\\sqrt{3}i}{2}=\\frac{-1+\\sqrt{3}i}{2}$$",
"result": "=-\\frac{-1+\\sqrt{3}i}{2}"
},
{
"type": "interim",
"title": "Rewrite $$-\\frac{-1+\\sqrt{3}i}{2}$$ in standard complex form: $$\\frac{1}{2}-\\frac{\\sqrt{3}}{2}i$$",
"input": "-\\frac{-1+\\sqrt{3}i}{2}",
"steps": [
{
"type": "step",
"primary": "Apply the fraction rule: $$\\frac{a\\pm\\:b}{c}=\\frac{a}{c}\\pm\\:\\frac{b}{c}$$",
"secondary": [
"$$\\frac{-1+\\sqrt{3}i}{2}=-\\left(-\\frac{1}{2}\\right)-\\left(\\frac{\\sqrt{3}i}{2}\\right)$$"
],
"result": "=-\\left(-\\frac{1}{2}\\right)-\\left(\\frac{\\sqrt{3}i}{2}\\right)"
},
{
"type": "step",
"primary": "Remove parentheses: $$\\left(a\\right)=a,\\:-\\left(-a\\right)=a$$",
"result": "=\\frac{1}{2}-\\frac{\\sqrt{3}i}{2}"
}
],
"meta": {
"interimType": "Rewrite In Complex Form Title 2Eq",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s74TqdRGDyv3oqElK9EevGS9z4F6b9EBEhpTHCu4QIJPQnVQZ9jTQhWaoOGaFYelMKfAu5u/TBlzVG5qXgF9PAhyjetd55DYlveZzsS8XHZnp6pfF1z6umzUJTJvt+ojYZwPTM+xnhoGkKkgIQ0VhzmNz4F6b9EBEhpTHCu4QIJPRMYix7/cTjHR2UPxtgKfavQO9djmXGGOQuWkFSRSz08+WvT9lR6dzrjAd/DNDcBv0="
}
},
{
"type": "step",
"result": "=\\frac{1}{2}-\\frac{\\sqrt{3}}{2}i"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Algebraic Manipulation Simplify Title 1Eq"
}
},
{
"type": "interim",
"title": "Simplify $$\\sqrt[3]{-1}\\frac{-1-\\sqrt{3}i}{2}:{\\quad}\\frac{1}{2}+i\\frac{\\sqrt{3}}{2}$$",
"input": "\\sqrt[3]{-1}\\frac{-1-\\sqrt{3}i}{2}",
"steps": [
{
"type": "interim",
"title": "$$\\sqrt[3]{-1}=-1$$",
"input": "\\sqrt[3]{-1}",
"steps": [
{
"type": "step",
"primary": "$$\\sqrt[n]{-1}=-1,\\:$$if $$n$$ is odd",
"secondary": [
"$$\\sqrt[3]{-1}=-1$$"
],
"result": "=-1"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Solver",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s76H1xoeptwwOonZRztLDv7i061ljBSPJeENOw2efoSWuixCfF7o9L2hRx9Shm0jmvo3oe/oyhMy2+1TQhDBd2f8qdr6Xp5CVvDj5nIWgDseQkt3WiGR7ZaCaXvz77bMjS"
}
},
{
"type": "step",
"result": "=-1\\cdot\\:\\frac{-1-\\sqrt{3}i}{2}"
},
{
"type": "step",
"primary": "Multiply: $$1\\cdot\\:\\frac{-1-\\sqrt{3}i}{2}=\\frac{-1-\\sqrt{3}i}{2}$$",
"result": "=-\\frac{-1-\\sqrt{3}i}{2}"
},
{
"type": "interim",
"title": "Rewrite $$-\\frac{-1-\\sqrt{3}i}{2}$$ in standard complex form: $$\\frac{1}{2}+\\frac{\\sqrt{3}}{2}i$$",
"input": "-\\frac{-1-\\sqrt{3}i}{2}",
"steps": [
{
"type": "step",
"primary": "Apply the fraction rule: $$\\frac{a\\pm\\:b}{c}=\\frac{a}{c}\\pm\\:\\frac{b}{c}$$",
"secondary": [
"$$\\frac{-1-\\sqrt{3}i}{2}=-\\left(-\\frac{1}{2}\\right)-\\left(-\\frac{\\sqrt{3}i}{2}\\right)$$"
],
"result": "=-\\left(-\\frac{1}{2}\\right)-\\left(-\\frac{\\sqrt{3}i}{2}\\right)"
},
{
"type": "step",
"primary": "Apply rule $$-\\left(-a\\right)=a$$",
"result": "=\\frac{1}{2}+\\frac{\\sqrt{3}i}{2}"
}
],
"meta": {
"interimType": "Rewrite In Complex Form Title 2Eq",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s74TqdRGDyv3oqElK9EevGS1BGfus/0qXQoc6ObyzUa30nVQZ9jTQhWaoOGaFYelMKfAu5u/TBlzVG5qXgF9PAhyjetd55DYlveZzsS8XHZnp6pfF1z6umzUJTJvt+ojYZwPTM+xnhoGkKkgIQ0VhzmFBGfus/0qXQoc6ObyzUa31MYix7/cTjHR2UPxtgKfavQO9djmXGGOQuWkFSRSz08+WvT9lR6dzrjAd/DNDcBv0="
}
},
{
"type": "step",
"result": "=\\frac{1}{2}+\\frac{\\sqrt{3}}{2}i"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Algebraic Manipulation Simplify Title 1Eq"
}
},
{
"type": "step",
"result": "u=-1,\\:u=\\frac{1}{2}-i\\frac{\\sqrt{3}}{2},\\:u=\\frac{1}{2}+i\\frac{\\sqrt{3}}{2}"
}
],
"meta": {
"solvingClass": "Equations",
"interimType": "Equations"
}
},
{
"type": "step",
"primary": "Substitute back $$u=\\sin\\left(x\\right)$$",
"result": "\\sin\\left(x\\right)=-1,\\:\\sin\\left(x\\right)=\\frac{1}{2}-i\\frac{\\sqrt{3}}{2},\\:\\sin\\left(x\\right)=\\frac{1}{2}+i\\frac{\\sqrt{3}}{2}"
}
],
"meta": {
"interimType": "Substitution Method 0Eq"
}
},
{
"type": "interim",
"title": "$$\\sin\\left(x\\right)=-1{\\quad:\\quad}x=\\frac{3π}{2}+2πn$$",
"input": "\\sin\\left(x\\right)=-1",
"steps": [
{
"type": "interim",
"title": "General solutions for $$\\sin\\left(x\\right)=-1$$",
"result": "x=\\frac{3π}{2}+2πn",
"steps": [
{
"type": "step",
"primary": "$$\\sin\\left(x\\right)$$ periodicity table with $$2πn$$ cycle:<br/>$$\\begin{array}{|c|c|c|c|}\\hline x&\\sin(x)&x&\\sin(x)\\\\\\hline 0&0&π&0\\\\\\hline \\frac{π}{6}&\\frac{1}{2}&\\frac{7π}{6}&-\\frac{1}{2}\\\\\\hline \\frac{π}{4}&\\frac{\\sqrt{2}}{2}&\\frac{5π}{4}&-\\frac{\\sqrt{2}}{2}\\\\\\hline \\frac{π}{3}&\\frac{\\sqrt{3}}{2}&\\frac{4π}{3}&-\\frac{\\sqrt{3}}{2}\\\\\\hline \\frac{π}{2}&1&\\frac{3π}{2}&-1\\\\\\hline \\frac{2π}{3}&\\frac{\\sqrt{3}}{2}&\\frac{5π}{3}&-\\frac{\\sqrt{3}}{2}\\\\\\hline \\frac{3π}{4}&\\frac{\\sqrt{2}}{2}&\\frac{7π}{4}&-\\frac{\\sqrt{2}}{2}\\\\\\hline \\frac{5π}{6}&\\frac{1}{2}&\\frac{11π}{6}&-\\frac{1}{2}\\\\\\hline \\end{array}$$"
},
{
"type": "step",
"result": "x=\\frac{3π}{2}+2πn"
}
],
"meta": {
"interimType": "Trig General Solutions sin 1Eq"
}
}
],
"meta": {
"interimType": "N/A"
}
},
{
"type": "interim",
"title": "$$\\sin\\left(x\\right)=\\frac{1}{2}-i\\frac{\\sqrt{3}}{2}{\\quad:\\quad}$$No Solution",
"input": "\\sin\\left(x\\right)=\\frac{1}{2}-i\\frac{\\sqrt{3}}{2}",
"steps": [
{
"type": "step",
"result": "\\mathrm{No\\:Solution}"
}
],
"meta": {
"interimType": "N/A"
}
},
{
"type": "interim",
"title": "$$\\sin\\left(x\\right)=\\frac{1}{2}+i\\frac{\\sqrt{3}}{2}{\\quad:\\quad}$$No Solution",
"input": "\\sin\\left(x\\right)=\\frac{1}{2}+i\\frac{\\sqrt{3}}{2}",
"steps": [
{
"type": "step",
"result": "\\mathrm{No\\:Solution}"
}
],
"meta": {
"interimType": "N/A"
}
},
{
"type": "step",
"primary": "Combine all the solutions",
"result": "x=\\frac{3π}{2}+2πn"
}
],
"meta": {
"solvingClass": "Trig Equations",
"practiceLink": "/practice/trigonometry-practice#area=main&subtopic=Trig%20Equations",
"practiceTopic": "Trig Equations"
}
},
"plot_output": {
"meta": {
"plotInfo": {
"variable": "x",
"plotRequest": "\\sin^{3}(x)+1"
},
"showViewLarger": true
}
},
"meta": {
"showVerify": true
}
}
Solution
Solution
+1
Degrees
Solution steps
Solve by substitution
Let:
For the solutions are
if is odd
Simplify
if is odd
Multiply:
Rewrite in standard complex form:
Apply the fraction rule:
Remove parentheses:
Simplify
if is odd
Multiply:
Rewrite in standard complex form:
Apply the fraction rule:
Apply rule
Substitute back
General solutions for
periodicity table with cycle:
No Solution
No Solution
Combine all the solutions
Graph
Popular Examples
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Frequently Asked Questions (FAQ)
What is the general solution for sin^3(x)=-1 ?
The general solution for sin^3(x)=-1 is x=(3pi)/2+2pin