What is the general solution for sin^{22}(x)=sin^2(x) ?

The general solution for sin^{22}(x)=sin^2(x) is x=2pin,x=pi+2pin,x= pi/2+2pin,x=(3pi)/2+2pin

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sin^{22}(x)=sin^2(x)

sin^{22} (x) = sin^{2} (x)

x = 2 πn, x = π + 2 πn, x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

Solution steps

sin^{22} (x) = sin^{2} (x)

Solve by substitution

sin (x) = 0, sin (x) = 1, sin (x) = - 1

sin (x) = 0 : x = 2 πn, x = π + 2 πn

sin (x) = 1 : x = \frac{π}{2} + 2 πn

sin (x) = - 1 : x = \frac{3 π}{2} + 2 πn

Combine all the solutions

x = 2 πn, x = π + 2 πn, x = \frac{π}{2} + 2 πn, x = \frac{3 π}{2} + 2 πn

sin^{2} (2 x) + cos^{2} (x) - 1 = 0

cos (8 t) - 5 sin (8 t) = 0

cos^{2} (x) + 3 sin (x) + 1 = 0

\frac{a ^{0.2}}{( cos ^{2} ( x ) ) - cos ^{2} ( x ) - 1} = 0

(\frac{2 cos ( x )}{2 - 1}) (\frac{sin ( x )}{2 + 2}) = 0

What is the general solution for sin^{22}(x)=sin^2(x) ?
The general solution for sin^{22}(x)=sin^2(x) is x=2pin,x=pi+2pin,x= pi/2+2pin,x=(3pi)/2+2pin