What is the general solution for tan^4(x)+tan^2(x)=tan(x) ?

The general solution for tan^4(x)+tan^2(x)=tan(x) is x=pin,x=0.59876…+pin

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tan^4(x)+tan^2(x)=tan(x)

tan^{4} (x) + tan^{2} (x) = tan (x)

x = πn, x = 0.59876 \dots + πn

Solution steps

tan^{4} (x) + tan^{2} (x) = tan (x)

Solve by substitution

tan (x) = 0, tan (x) \approx 0.68232 \dots

tan (x) = 0 : x = πn

tan (x) = 0.68232 \dots : x = arctan (0.68232 \dots) + πn

Combine all the solutions

x = πn, x = arctan (0.68232 \dots) + πn

Show solutions in decimal form

x = πn, x = 0.59876 \dots + πn

sin^{4} (x) + sin^{2} (x) = sin^{6} (x)

cos (a) = \frac{- 11}{14}

x, sin (\frac{x}{x}) = 0.7

5 cos^{2} (x) + sin^{2} (x) = 4

cos (u) - 1.5 sin^{2} (u) + 0.1667 = 0

What is the general solution for tan^4(x)+tan^2(x)=tan(x) ?
The general solution for tan^4(x)+tan^2(x)=tan(x) is x=pin,x=0.59876…+pin