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Popular Trigonometry >

2cos^2(x)=sqrt(3)*cos(x)

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Solution

2cos2(x)=3​⋅cos(x)

Solution

x=2π​+2πn,x=23π​+2πn,x=6π​+2πn,x=611π​+2πn
+1
Degrees
x=90∘+360∘n,x=270∘+360∘n,x=30∘+360∘n,x=330∘+360∘n
Solution steps
2cos2(x)=3​cos(x)
Solve by substitution
2cos2(x)=3​cos(x)
Let: cos(x)=u2u2=3​u
2u2=3​u:u=0,u=23​​
2u2=3​u
Move 3​uto the left side
2u2=3​u
Subtract 3​u from both sides2u2−3​u=3​u−3​u
Simplify2u2−3​u=0
2u2−3​u=0
Factor 2u2−3​u:u(2u−3​)
2u2−3​u
Apply exponent rule: ab+c=abacu2=uu=2uu−3​u
Factor out common term u=u(2u−1⋅23​)
Multiply the numbers: 1⋅2=2=u(2u−3​)
u(2u−3​)=0
Using the Zero Factor Principle: If ab=0then a=0or b=0u=0or2u−3​=0
Solve 2u−3​=0:u=23​​
2u−3​=0
Move 3​to the right side
2u−3​=0
Add 3​ to both sides2u−3​+3​=0+3​
Simplify2u=3​
2u=3​
Divide both sides by 2
2u=3​
Divide both sides by 222u​=23​​
Simplifyu=23​​
u=23​​
The solutions to the quadratic equation are:u=0,u=23​​
Substitute back u=cos(x)cos(x)=0,cos(x)=23​​
cos(x)=0,cos(x)=23​​
cos(x)=0:x=2π​+2πn,x=23π​+2πn
cos(x)=0
General solutions for cos(x)=0
cos(x) periodicity table with 2πn cycle:
x06π​4π​3π​2π​32π​43π​65π​​cos(x)123​​22​​21​0−21​−22​​−23​​​xπ67π​45π​34π​23π​35π​47π​611π​​cos(x)−1−23​​−22​​−21​021​22​​23​​​​
x=2π​+2πn,x=23π​+2πn
x=2π​+2πn,x=23π​+2πn
cos(x)=23​​:x=6π​+2πn,x=611π​+2πn
cos(x)=23​​
General solutions for cos(x)=23​​
cos(x) periodicity table with 2πn cycle:
x06π​4π​3π​2π​32π​43π​65π​​cos(x)123​​22​​21​0−21​−22​​−23​​​xπ67π​45π​34π​23π​35π​47π​611π​​cos(x)−1−23​​−22​​−21​021​22​​23​​​​
x=6π​+2πn,x=611π​+2πn
x=6π​+2πn,x=611π​+2πn
Combine all the solutionsx=2π​+2πn,x=23π​+2πn,x=6π​+2πn,x=611π​+2πn

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