What is the general solution for sqrt(2)*sin(x)+1=0 ?

The general solution for sqrt(2)*sin(x)+1=0 is x=(5pi)/4+2pin,x=(7pi)/4+2pin

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sqrt(2)*sin(x)+1=0

2 \cdot sin (x) + 1 = 0

x = \frac{5 π}{4} + 2 πn, x = \frac{7 π}{4} + 2 πn

Solution steps

2 sin (x) + 1 = 0

Move

1

to the right side

2 sin (x) = - 1

Divide both sides by

2

sin (x) = - \frac{2}{2}

General solutions for

sin (x) = - \frac{2}{2}

x = \frac{5 π}{4} + 2 πn, x = \frac{7 π}{4} + 2 πn

5 cos^{2} (2 x) + 4 cos^{2} (x) - 5 = 0

sin (3 x + 10) = cos (x + 2 4^{\circ})

tan (x^{2}) + 1 = 0

\frac{( 1 + cos ^{2} ( a ) )}{sin ^{2} ( a )} = \frac{5}{3}

d^{2} + 13 d + 36 = \frac{sin ^{2} ( x )}{2}

What is the general solution for sqrt(2)*sin(x)+1=0 ?
The general solution for sqrt(2)*sin(x)+1=0 is x=(5pi)/4+2pin,x=(7pi)/4+2pin