What is the general solution for b= 3/((cot(x))) ?

The general solution for b= 3/((cot(x))) is x=arccot(3/b)+pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

b= 3/((cot(x)))

b = \frac{3}{( cot ( x ) )}

x = arccot (\frac{3}{b}) + πn

Solution steps

b = \frac{3}{( cot ( x ) )}

Switch sides

\frac{3}{cot ( x )} = b

Multiply both sides by

cot (x)

3 = b cot (x)

Switch sides

b cot (x) = 3

Divide both sides by

b; b \neq = 0

cot (x) = \frac{3}{b}; b \neq = 0

Apply trig inverse properties

x = arccot (\frac{3}{b}) + πn

4 sin^{2} (x) + cos (x) + 1 = 0

(cot^{2} (x)) - csc (x) = 1

x, u = arctan (\frac{x}{y})

4 cos^{2} (2 x - 1) = 1

sin^{2} (x) - 2 cos^{2} (x) + cos^{2} (x) = 0

What is the general solution for b= 3/((cot(x))) ?
The general solution for b= 3/((cot(x))) is x=arccot(3/b)+pin