What is the general solution for 5cos(5x)=2 ?

The general solution for 5cos(5x)=2 is x=(1.15927…)/5+(2pin)/5 ,x=(2pi)/5-(1.15927…)/5+(2pin)/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5cos(5x)=2

5 cos (5 x) = 2

x = \frac{1.15927 \dots}{5} + \frac{2 πn}{5}, x = \frac{2 π}{5} - \frac{1.15927 \dots}{5} + \frac{2 πn}{5}

Solution steps

5 cos (5 x) = 2

Divide both sides by

5

cos (5 x) = \frac{2}{5}

Apply trig inverse properties

5 x = arccos (\frac{2}{5}) + 2 πn, 5 x = 2 π - arccos (\frac{2}{5}) + 2 πn

Solve

5 x = arccos (\frac{2}{5}) + 2 πn : x = \frac{arccos ( \frac{2}{5} )}{5} + \frac{2 πn}{5}

Solve

5 x = 2 π - arccos (\frac{2}{5}) + 2 πn : x = \frac{2 π}{5} - \frac{arccos ( \frac{2}{5} )}{5} + \frac{2 πn}{5}

x = \frac{arccos ( \frac{2}{5} )}{5} + \frac{2 πn}{5}, x = \frac{2 π}{5} - \frac{arccos ( \frac{2}{5} )}{5} + \frac{2 πn}{5}

Show solutions in decimal form

x = \frac{1.15927 \dots}{5} + \frac{2 πn}{5}, x = \frac{2 π}{5} - \frac{1.15927 \dots}{5} + \frac{2 πn}{5}

4 sin (x) - sin^{3} (x) - 1 = 0

1 - tan (a) = \frac{- 1}{3}

tan^{2} (x) + cos^{2} (x) - 1 = 0

cot^{3} (x) + cot (x) = 0

21 + 18 cos (x) = 16 (1 - cos^{2} (x))

What is the general solution for 5cos(5x)=2 ?
The general solution for 5cos(5x)=2 is x=(1.15927…)/5+(2pin)/5 ,x=(2pi)/5-(1.15927…)/5+(2pin)/5