What is the general solution for 4cos(θ)=sqrt(2)+2cos(θ) ?

The general solution for 4cos(θ)=sqrt(2)+2cos(θ) is θ= pi/4+2pin,θ=(7pi)/4+2pin

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4cos(θ)=sqrt(2)+2cos(θ)

4 cos (θ) = 2 + 2 cos (θ)

θ = \frac{π}{4} + 2 πn, θ = \frac{7 π}{4} + 2 πn

Solution steps

4 cos (θ) = 2 + 2 cos (θ)

Solve by substitution

cos (θ) = \frac{2}{2}

cos (θ) = \frac{2}{2} : θ = \frac{π}{4} + 2 πn, θ = \frac{7 π}{4} + 2 πn

Combine all the solutions

θ = \frac{π}{4} + 2 πn, θ = \frac{7 π}{4} + 2 πn

x, T (6) = 3.15 cos (\frac{π}{6} x) + 19.15

3 tan^{2} (x) = 1, - π \leq x \leq π

cos (2 t) - cos (t) = 0.5

0 = - 6 csc (x) cot (x)

0.08 = 0.12 cos^{2} (3.922 t)

What is the general solution for 4cos(θ)=sqrt(2)+2cos(θ) ?
The general solution for 4cos(θ)=sqrt(2)+2cos(θ) is θ= pi/4+2pin,θ=(7pi)/4+2pin