{
"query": {
"display": "$$\\cos\\left(2t\\right)-\\cos\\left(t\\right)=0.5$$",
"symbolab_question": "EQUATION#\\cos(2t)-\\cos(t)=0.5"
},
"solution": {
"level": "PERFORMED",
"subject": "Trigonometry",
"topic": "Trig Equations",
"subTopic": "Trig Equations",
"default": "t=2.28020…+2πn,t=-2.28020…+2πn",
"degrees": "t=130.64631…^{\\circ }+360^{\\circ }n,t=-130.64631…^{\\circ }+360^{\\circ }n",
"meta": {
"showVerify": true
}
},
"steps": {
"type": "interim",
"title": "$$\\cos\\left(2t\\right)-\\cos\\left(t\\right)=0.5{\\quad:\\quad}t=2.28020…+2πn,\\:t=-2.28020…+2πn$$",
"input": "\\cos\\left(2t\\right)-\\cos\\left(t\\right)=0.5",
"steps": [
{
"type": "step",
"primary": "Subtract $$0.5$$ from both sides",
"result": "\\cos\\left(2t\\right)-\\cos\\left(t\\right)-0.5=0"
},
{
"type": "interim",
"title": "Rewrite using trig identities",
"input": "-0.5+\\cos\\left(2t\\right)-\\cos\\left(t\\right)",
"result": "-1.5-\\cos\\left(t\\right)+2\\cos^{2}\\left(t\\right)=0",
"steps": [
{
"type": "step",
"primary": "Use the Double Angle identity: $$\\cos\\left(2x\\right)=2\\cos^{2}\\left(x\\right)-1$$",
"result": "=-0.5+2\\cos^{2}\\left(t\\right)-1-\\cos\\left(t\\right)"
},
{
"type": "interim",
"title": "Simplify $$-0.5+2\\cos^{2}\\left(t\\right)-1-\\cos\\left(t\\right):{\\quad}2\\cos^{2}\\left(t\\right)-\\cos\\left(t\\right)-1.5$$",
"input": "-0.5+2\\cos^{2}\\left(t\\right)-1-\\cos\\left(t\\right)",
"result": "=2\\cos^{2}\\left(t\\right)-\\cos\\left(t\\right)-1.5",
"steps": [
{
"type": "step",
"primary": "Group like terms",
"result": "=2\\cos^{2}\\left(t\\right)-\\cos\\left(t\\right)-0.5-1"
},
{
"type": "step",
"primary": "Subtract the numbers: $$-0.5-1=-1.5$$",
"result": "=2\\cos^{2}\\left(t\\right)-\\cos\\left(t\\right)-1.5"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Generic Simplify Specific 1Eq",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s7BqoZ2G4jxp4E6VyWXdlno9j8zfwYjEGCr5E33o5mvjMtOtZYwUjyXhDTsNnn6ElriOB8hTxY3wN8anamyuwHt1vwNn2oBW9s42jy6BdZRon5c/qFgsAjumWdecXSXImfHjb2+5NLFZrsH9fcPWg/TZhli5XxLXqgnZrAO26BLBqgp7Nx+qXcYrKAbQBXv+X7PH5ZD6aFl7Cbfthb/5gVxA=="
}
}
],
"meta": {
"interimType": "Trig Rewrite Using Trig identities 0Eq",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s7rrqBN2OyzpnjR5QUtF+XjQB5F+rwllWIX7ue4YyB0LQUOLSbMox6vSWmoo6JD5Rw6oDeFBEXdI8LVv9QsNOFoRacrm3LsJ1aIjJN65AlUxeJDKsu+SuqQAE/BN/8mXKTenAS7uHRcrNuY/YiV2CuSe/i1qBOrdmwxPB+GDbCRqnwt9LEn7QCBUukJKctfSJKk2VQdqPGsmYTaYyesllHTRc4KXs8xgJNiLkJwr0b/5OJqVxX90jlMfh9fKn6dzC4"
}
},
{
"type": "interim",
"title": "Solve by substitution",
"input": "-1.5-\\cos\\left(t\\right)+2\\cos^{2}\\left(t\\right)=0",
"result": "\\cos\\left(t\\right)=\\frac{1+\\sqrt{13}}{4},\\:\\cos\\left(t\\right)=\\frac{1-\\sqrt{13}}{4}",
"steps": [
{
"type": "step",
"primary": "Let: $$\\cos\\left(t\\right)=u$$",
"result": "-1.5-u+2u^{2}=0"
},
{
"type": "interim",
"title": "$$-1.5-u+2u^{2}=0{\\quad:\\quad}u=\\frac{1+\\sqrt{13}}{4},\\:u=\\frac{1-\\sqrt{13}}{4}$$",
"input": "-1.5-u+2u^{2}=0",
"steps": [
{
"type": "interim",
"title": "Multiply both sides by $$10$$",
"input": "-1.5-u+2u^{2}=0",
"result": "-15-10u+20u^{2}=0",
"steps": [
{
"type": "step",
"primary": "To eliminate decimal points, multiply by 10 for every digit after the decimal point",
"secondary": [
"There is one digit to the right of the decimal point, therefore multiply by $$10$$"
],
"result": "-1.5\\cdot\\:10-u\\cdot\\:10+2u^{2}\\cdot\\:10=0\\cdot\\:10"
},
{
"type": "step",
"primary": "Refine",
"result": "-15-10u+20u^{2}=0"
}
],
"meta": {
"interimType": "Multiply Both Sides Specific 1Eq",
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}
},
{
"type": "step",
"primary": "Write in the standard form $$ax^{2}+bx+c=0$$",
"result": "20u^{2}-10u-15=0"
},
{
"type": "interim",
"title": "Solve with the quadratic formula",
"input": "20u^{2}-10u-15=0",
"result": "{u}_{1,\\:2}=\\frac{-\\left(-10\\right)\\pm\\:\\sqrt{\\left(-10\\right)^{2}-4\\cdot\\:20\\left(-15\\right)}}{2\\cdot\\:20}",
"steps": [
{
"type": "definition",
"title": "Quadratic Equation Formula:",
"text": "For a quadratic equation of the form $$ax^2+bx+c=0$$ the solutions are <br/>$${\\quad}x_{1,\\:2}=\\frac{-b\\pm\\sqrt{b^2-4ac}}{2a}$$"
},
{
"type": "step",
"primary": "For $${\\quad}a=20,\\:b=-10,\\:c=-15$$",
"result": "{u}_{1,\\:2}=\\frac{-\\left(-10\\right)\\pm\\:\\sqrt{\\left(-10\\right)^{2}-4\\cdot\\:20\\left(-15\\right)}}{2\\cdot\\:20}"
}
],
"meta": {
"interimType": "Solving The Quadratic Equation With Quadratic Formula Definition 0Eq",
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}
},
{
"type": "interim",
"title": "$$\\sqrt{\\left(-10\\right)^{2}-4\\cdot\\:20\\left(-15\\right)}=10\\sqrt{13}$$",
"input": "\\sqrt{\\left(-10\\right)^{2}-4\\cdot\\:20\\left(-15\\right)}",
"result": "{u}_{1,\\:2}=\\frac{-\\left(-10\\right)\\pm\\:10\\sqrt{13}}{2\\cdot\\:20}",
"steps": [
{
"type": "step",
"primary": "Apply rule $$-\\left(-a\\right)=a$$",
"result": "=\\sqrt{\\left(-10\\right)^{2}+4\\cdot\\:20\\cdot\\:15}"
},
{
"type": "step",
"primary": "Apply exponent rule: $$\\left(-a\\right)^{n}=a^{n},\\:$$if $$n$$ is even",
"secondary": [
"$$\\left(-10\\right)^{2}=10^{2}$$"
],
"result": "=\\sqrt{10^{2}+4\\cdot\\:20\\cdot\\:15}"
},
{
"type": "step",
"primary": "Multiply the numbers: $$4\\cdot\\:20\\cdot\\:15=1200$$",
"result": "=\\sqrt{10^{2}+1200}"
},
{
"type": "step",
"primary": "$$10^{2}=100$$",
"result": "=\\sqrt{100+1200}"
},
{
"type": "step",
"primary": "Add the numbers: $$100+1200=1300$$",
"result": "=\\sqrt{1300}"
},
{
"type": "interim",
"title": "Prime factorization of $$1300:{\\quad}2^{2}\\cdot\\:5^{2}\\cdot\\:13$$",
"input": "1300",
"result": "=\\sqrt{2^{2}\\cdot\\:5^{2}\\cdot\\:13}",
"steps": [
{
"type": "step",
"primary": "$$1300\\:$$divides by $$2\\quad\\:1300=650\\cdot\\:2$$",
"result": "=2\\cdot\\:650"
},
{
"type": "step",
"primary": "$$650\\:$$divides by $$2\\quad\\:650=325\\cdot\\:2$$",
"result": "=2\\cdot\\:2\\cdot\\:325"
},
{
"type": "step",
"primary": "$$325\\:$$divides by $$5\\quad\\:325=65\\cdot\\:5$$",
"result": "=2\\cdot\\:2\\cdot\\:5\\cdot\\:65"
},
{
"type": "step",
"primary": "$$65\\:$$divides by $$5\\quad\\:65=13\\cdot\\:5$$",
"result": "=2\\cdot\\:2\\cdot\\:5\\cdot\\:5\\cdot\\:13"
},
{
"type": "step",
"primary": "$$2,\\:5,\\:13$$ are all prime numbers, therefore no further factorization is possible",
"result": "=2\\cdot\\:2\\cdot\\:5\\cdot\\:5\\cdot\\:13"
},
{
"type": "step",
"result": "=2^{2}\\cdot\\:5^{2}\\cdot\\:13"
}
],
"meta": {
"solvingClass": "Composite Integer",
"interimType": "Prime Fac 1Eq",
"gptData": "pG0PljGlka7rWtIVHz2xyoU2cWyPLDgE1QLLHeauuc3PHQdChPJ2JhfqHT+ZU0OMrfn8NOj0LUzuzje6xTyxRvTIRluRNPwUULD5JCqpmdzlQpqXZdOp1ODEbM70NuQa+ZE2CuWYXhz/1zRh+DBwSWJYgvXjl1/GaaWGY6UA4hGVE/90DxkmiXfmFDUpmLWr"
}
},
{
"type": "step",
"primary": "Apply radical rule: $$\\sqrt[n]{ab}=\\sqrt[n]{a}\\sqrt[n]{b}$$",
"result": "=\\sqrt{13}\\sqrt{2^{2}}\\sqrt{5^{2}}",
"meta": {
"practiceLink": "/practice/radicals-practice",
"practiceTopic": "Radical Rules"
}
},
{
"type": "step",
"primary": "Apply radical rule: $$\\sqrt[n]{a^n}=a$$",
"secondary": [
"$$\\sqrt{2^{2}}=2$$"
],
"result": "=2\\sqrt{13}\\sqrt{5^{2}}",
"meta": {
"practiceLink": "/practice/radicals-practice",
"practiceTopic": "Radical Rules"
}
},
{
"type": "step",
"primary": "Apply radical rule: $$\\sqrt[n]{a^n}=a$$",
"secondary": [
"$$\\sqrt{5^{2}}=5$$"
],
"result": "=2\\cdot\\:5\\sqrt{13}",
"meta": {
"practiceLink": "/practice/radicals-practice",
"practiceTopic": "Radical Rules"
}
},
{
"type": "step",
"primary": "Refine",
"result": "=10\\sqrt{13}"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Solver",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s7xYKyhiwThaKsz2Tl55KkNCSDE5ZXiT7i0G6OHwfSBwlucrZDjeKCXHUZNhNytfd/o5FYteSPKwXny4uCMrdsKzbZ4FbVup0SkWLdsUlh7BiGPrKVLAeMmSZA8offj7t/W80sdbB1u2v2qyNh5c5IvLFqBAt5T67Tq8n98acoS6mvdIV+S/e6Y0xIlZs2Mpn1"
}
},
{
"type": "step",
"primary": "Separate the solutions",
"result": "{u}_{1}=\\frac{-\\left(-10\\right)+10\\sqrt{13}}{2\\cdot\\:20},\\:{u}_{2}=\\frac{-\\left(-10\\right)-10\\sqrt{13}}{2\\cdot\\:20}"
},
{
"type": "interim",
"title": "$$u=\\frac{-\\left(-10\\right)+10\\sqrt{13}}{2\\cdot\\:20}:{\\quad}\\frac{1+\\sqrt{13}}{4}$$",
"input": "\\frac{-\\left(-10\\right)+10\\sqrt{13}}{2\\cdot\\:20}",
"steps": [
{
"type": "step",
"primary": "Apply rule $$-\\left(-a\\right)=a$$",
"result": "=\\frac{10+10\\sqrt{13}}{2\\cdot\\:20}"
},
{
"type": "step",
"primary": "Multiply the numbers: $$2\\cdot\\:20=40$$",
"result": "=\\frac{10+10\\sqrt{13}}{40}"
},
{
"type": "interim",
"title": "Factor $$10+10\\sqrt{13}:{\\quad}10\\left(1+\\sqrt{13}\\right)$$",
"input": "10+10\\sqrt{13}",
"result": "=\\frac{10\\left(1+\\sqrt{13}\\right)}{40}",
"steps": [
{
"type": "step",
"primary": "Rewrite as",
"result": "=10\\cdot\\:1+10\\sqrt{13}"
},
{
"type": "step",
"primary": "Factor out common term $$10$$",
"result": "=10\\left(1+\\sqrt{13}\\right)",
"meta": {
"practiceLink": "/practice/factoring-practice",
"practiceTopic": "Factoring"
}
}
],
"meta": {
"interimType": "Algebraic Manipulation Factor Title 1Eq"
}
},
{
"type": "step",
"primary": "Cancel the common factor: $$10$$",
"result": "=\\frac{1+\\sqrt{13}}{4}"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Solver",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s79/ul7VUbFVJ26S67qVBPqYW5HOGna/RaXa/Gk09/Z4PWpsRiJtjAg9hOGwXNhKOvA585Wz2Y8ioMtXlAhbC3eT/T0/f0601DgXfK88BhMN23W9KZmrXNYoAN18UqX8DRQWI3C7Ag9M6KUYO8l4hxQHrSBc9g/Ric4s/oUP5h9w6otGg9ku5UmRJdiMk4VVplDXnKs87BlN0+mj3MLu4hIw=="
}
},
{
"type": "interim",
"title": "$$u=\\frac{-\\left(-10\\right)-10\\sqrt{13}}{2\\cdot\\:20}:{\\quad}\\frac{1-\\sqrt{13}}{4}$$",
"input": "\\frac{-\\left(-10\\right)-10\\sqrt{13}}{2\\cdot\\:20}",
"steps": [
{
"type": "step",
"primary": "Apply rule $$-\\left(-a\\right)=a$$",
"result": "=\\frac{10-10\\sqrt{13}}{2\\cdot\\:20}"
},
{
"type": "step",
"primary": "Multiply the numbers: $$2\\cdot\\:20=40$$",
"result": "=\\frac{10-10\\sqrt{13}}{40}"
},
{
"type": "interim",
"title": "Factor $$10-10\\sqrt{13}:{\\quad}10\\left(1-\\sqrt{13}\\right)$$",
"input": "10-10\\sqrt{13}",
"result": "=\\frac{10\\left(1-\\sqrt{13}\\right)}{40}",
"steps": [
{
"type": "step",
"primary": "Rewrite as",
"result": "=10\\cdot\\:1-10\\sqrt{13}"
},
{
"type": "step",
"primary": "Factor out common term $$10$$",
"result": "=10\\left(1-\\sqrt{13}\\right)",
"meta": {
"practiceLink": "/practice/factoring-practice",
"practiceTopic": "Factoring"
}
}
],
"meta": {
"interimType": "Algebraic Manipulation Factor Title 1Eq"
}
},
{
"type": "step",
"primary": "Cancel the common factor: $$10$$",
"result": "=\\frac{1-\\sqrt{13}}{4}"
}
],
"meta": {
"solvingClass": "Solver",
"interimType": "Solver",
"gptData": "pG0PljGlka7rWtIVHz2xymbOTBTIQkBEGSNjyYYsjjDErT97kX84sZPuiUzCW6s7fFFzGKGpQqH1+arANkx3PoW5HOGna/RaXa/Gk09/Z4PWpsRiJtjAg9hOGwXNhKOvA585Wz2Y8ioMtXlAhbC3eVgQFGmNsbNcgLmy9BJd1ju3W9KZmrXNYoAN18UqX8DRQWI3C7Ag9M6KUYO8l4hxQOz1AwEVb+AUK8qLtzuQnMGotGg9ku5UmRJdiMk4VVplDXnKs87BlN0+mj3MLu4hIw=="
}
},
{
"type": "step",
"primary": "The solutions to the quadratic equation are:",
"result": "u=\\frac{1+\\sqrt{13}}{4},\\:u=\\frac{1-\\sqrt{13}}{4}"
}
],
"meta": {
"solvingClass": "Equations",
"interimType": "Equations"
}
},
{
"type": "step",
"primary": "Substitute back $$u=\\cos\\left(t\\right)$$",
"result": "\\cos\\left(t\\right)=\\frac{1+\\sqrt{13}}{4},\\:\\cos\\left(t\\right)=\\frac{1-\\sqrt{13}}{4}"
}
],
"meta": {
"interimType": "Substitution Method 0Eq"
}
},
{
"type": "interim",
"title": "$$\\cos\\left(t\\right)=\\frac{1+\\sqrt{13}}{4}{\\quad:\\quad}$$No Solution",
"input": "\\cos\\left(t\\right)=\\frac{1+\\sqrt{13}}{4}",
"steps": [
{
"type": "step",
"primary": "$$-1\\le\\cos\\left(x\\right)\\le1$$",
"result": "\\mathrm{No\\:Solution}"
}
],
"meta": {
"interimType": "N/A"
}
},
{
"type": "interim",
"title": "$$\\cos\\left(t\\right)=\\frac{1-\\sqrt{13}}{4}{\\quad:\\quad}t=\\arccos\\left(\\frac{1-\\sqrt{13}}{4}\\right)+2πn,\\:t=-\\arccos\\left(\\frac{1-\\sqrt{13}}{4}\\right)+2πn$$",
"input": "\\cos\\left(t\\right)=\\frac{1-\\sqrt{13}}{4}",
"steps": [
{
"type": "interim",
"title": "Apply trig inverse properties",
"input": "\\cos\\left(t\\right)=\\frac{1-\\sqrt{13}}{4}",
"result": "t=\\arccos\\left(\\frac{1-\\sqrt{13}}{4}\\right)+2πn,\\:t=-\\arccos\\left(\\frac{1-\\sqrt{13}}{4}\\right)+2πn",
"steps": [
{
"type": "step",
"primary": "General solutions for $$\\cos\\left(t\\right)=\\frac{1-\\sqrt{13}}{4}$$",
"secondary": [
"$$\\cos\\left(x\\right)=-a\\quad\\Rightarrow\\quad\\:x=\\arccos\\left(-a\\right)+2πn,\\:\\quad\\:x=-\\arccos\\left(-a\\right)+2πn$$"
],
"result": "t=\\arccos\\left(\\frac{1-\\sqrt{13}}{4}\\right)+2πn,\\:t=-\\arccos\\left(\\frac{1-\\sqrt{13}}{4}\\right)+2πn"
}
],
"meta": {
"interimType": "Trig Apply Inverse Props 0Eq"
}
}
],
"meta": {
"interimType": "N/A"
}
},
{
"type": "step",
"primary": "Combine all the solutions",
"result": "t=\\arccos\\left(\\frac{1-\\sqrt{13}}{4}\\right)+2πn,\\:t=-\\arccos\\left(\\frac{1-\\sqrt{13}}{4}\\right)+2πn"
},
{
"type": "step",
"primary": "Show solutions in decimal form",
"result": "t=2.28020…+2πn,\\:t=-2.28020…+2πn"
}
],
"meta": {
"solvingClass": "Trig Equations",
"practiceLink": "/practice/trigonometry-practice#area=main&subtopic=Trig%20Equations",
"practiceTopic": "Trig Equations"
}
},
"plot_output": {
"meta": {
"plotInfo": {
"variable": "t",
"plotRequest": "\\cos(2t)-\\cos(t)-0.5"
},
"showViewLarger": true
}
},
"meta": {
"showVerify": true
}
}
Solution
Solution
+1
Degrees
Solution steps
Subtract from both sides
Rewrite using trig identities
Use the Double Angle identity:
Simplify
Group like terms
Subtract the numbers:
Solve by substitution
Let:
Multiply both sides by
To eliminate decimal points, multiply by 10 for every digit after the decimal pointThere is one digit to the right of the decimal point, therefore multiply by
Refine
Write in the standard form
Solve with the quadratic formula
Quadratic Equation Formula:
For
Apply rule
Apply exponent rule: if is even
Multiply the numbers:
Add the numbers:
Prime factorization of
divides by
divides by
divides by
divides by
are all prime numbers, therefore no further factorization is possible
Apply radical rule:
Apply radical rule:
Apply radical rule:
Refine
Separate the solutions
Apply rule
Multiply the numbers:
Factor
Rewrite as
Factor out common term
Cancel the common factor:
Apply rule
Multiply the numbers:
Factor
Rewrite as
Factor out common term
Cancel the common factor:
The solutions to the quadratic equation are:
Substitute back
No Solution
Apply trig inverse properties
General solutions for
Combine all the solutions
Show solutions in decimal form
Graph
Popular Examples
0=-6csc(x)cot(x)0.08=0.12cos^2(3.922t)(15)/(sin(32))=(12)/(sin(b))(sin(x))/(25)=(sin(125))/(165.6)2cos(3θ)-1=0
Frequently Asked Questions (FAQ)
What is the general solution for cos(2t)-cos(t)=0.5 ?
The general solution for cos(2t)-cos(t)=0.5 is t=2.28020…+2pin,t=-2.28020…+2pin