What is the general solution for 8cos(6x)=2 ?

The general solution for 8cos(6x)=2 is x=(1.31811…)/6+(pin)/3 ,x= pi/3-(1.31811…)/6+(pin)/3

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8cos(6x)=2

8 cos (6 x) = 2

x = \frac{1.31811 \dots}{6} + \frac{πn}{3}, x = \frac{π}{3} - \frac{1.31811 \dots}{6} + \frac{πn}{3}

Solution steps

8 cos (6 x) = 2

Divide both sides by

8

cos (6 x) = \frac{1}{4}

Apply trig inverse properties

6 x = arccos (\frac{1}{4}) + 2 πn, 6 x = 2 π - arccos (\frac{1}{4}) + 2 πn

Solve

6 x = arccos (\frac{1}{4}) + 2 πn : x = \frac{arccos ( \frac{1}{4} )}{6} + \frac{πn}{3}

Solve

6 x = 2 π - arccos (\frac{1}{4}) + 2 πn : x = \frac{π}{3} - \frac{arccos ( \frac{1}{4} )}{6} + \frac{πn}{3}

x = \frac{arccos ( \frac{1}{4} )}{6} + \frac{πn}{3}, x = \frac{π}{3} - \frac{arccos ( \frac{1}{4} )}{6} + \frac{πn}{3}

Show solutions in decimal form

x = \frac{1.31811 \dots}{6} + \frac{πn}{3}, x = \frac{π}{3} - \frac{1.31811 \dots}{6} + \frac{πn}{3}

sin (x) = \frac{- ( 6 )}{( 7 ) cos ( x )}

5^{2} = 8^{2} - (11.85)^{2} - 2 (8) (11.85) (cos (A))

2 + 2 sin (θ) = 4

- 4 sin (8 x) = 0

- sin (x) + 2 cos (x) = 0

What is the general solution for 8cos(6x)=2 ?
The general solution for 8cos(6x)=2 is x=(1.31811…)/6+(pin)/3 ,x= pi/3-(1.31811…)/6+(pin)/3