What is the general solution for csc(θ)+1=0,(0,2pi) ?

The general solution for csc(θ)+1=0,(0,2pi) is θ=(3pi)/2

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csc(θ)+1=0,(0,2pi)

csc (θ) + 1 = 0, (0, 2 π)

θ = \frac{3 π}{2}

Solution steps

csc (θ) + 1 = 0, (0, 2 π)

Move

1

to the right side

csc (θ) = - 1

General solutions for

csc (θ) = - 1

θ = \frac{3 π}{2} + 2 πn

Solutions for the range

(0, 2 π)

θ = \frac{3 π}{2}

x, y^{2} = - 2 tan (2 x)

2 cos^{2} (a) - 3 cos (a) + 1 = 0

sin (x) \cdot cos (2 x) = 0.5 - sin (2 x) \cdot cos (x)

tan (x) = 0.625

4 sin^{2} (2 θ) + 6 = 9

What is the general solution for csc(θ)+1=0,(0,2pi) ?
The general solution for csc(θ)+1=0,(0,2pi) is θ=(3pi)/2