What is the general solution for arctan(x^2-2x)=0 ?

The general solution for arctan(x^2-2x)=0 is x=2,x=0

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arctan(x^2-2x)=0

arctan (x^{2} - 2 x) = 0

x = 2, x = 0

Solution steps

arctan (x^{2} - 2 x) = 0

Apply trig inverse properties

x^{2} - 2 x = 0

Solve

x^{2} - 2 x = 0 : x = 2, x = 0

x = 2, x = 0

sin (x^{\circ}) = \frac{6.57 \cdot 1 0 ^{- 7}}{1.8 \cdot 1 0 ^{- 6}}

3 sin^{2} (x) + cos^{2} (x) = 3 sin (x)

y, x tan (y) - x^{2} sin (x) + 3 x^{3} = 0

(\frac{( 1 - sin ^{2} ( x ) )}{( 1 + 2 \cdot sin ^{2} ( x ) )}) = 0.45

- 5 sin (t) = 0

What is the general solution for arctan(x^2-2x)=0 ?
The general solution for arctan(x^2-2x)=0 is x=2,x=0