What is the general solution for cos(θ)=(-3+(-6))/((sqrt(9))(\sqrt{18))} ?

The general solution for cos(θ)=(-3+(-6))/((sqrt(9))(\sqrt{18))} is θ=(3pi)/4+2pin,θ=(5pi)/4+2pin

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cos(θ)=(-3+(-6))/((sqrt(9))(\sqrt{18))}

cos (θ) = \frac{- 3 + ( - 6 )}{( 9 ) ( 18 )}

θ = \frac{3 π}{4} + 2 πn, θ = \frac{5 π}{4} + 2 πn

Solution steps

cos (θ) = \frac{- 3 + ( - 6 )}{( 9 ) ( 18 )}

Simplify

\frac{- 3 - 6}{9 18} : - \frac{2}{2}

General solutions for

cos (θ) = - \frac{2}{2}

θ = \frac{3 π}{4} + 2 πn, θ = \frac{5 π}{4} + 2 πn

sin (\frac{6}{x}) = 36

8 cos (2 x) + 6 = cos^{2} (x) + cos (x)

tan (x) = \frac{200}{500}

cos (2 x) + sin (- x) - 2 = 0

sec (θ) = tan (θ)

What is the general solution for cos(θ)=(-3+(-6))/((sqrt(9))(\sqrt{18))} ?
The general solution for cos(θ)=(-3+(-6))/((sqrt(9))(\sqrt{18))} is θ=(3pi)/4+2pin,θ=(5pi)/4+2pin