What is the general solution for cos(2x)+sin(-x)-2=0 ?

The general solution for cos(2x)+sin(-x)-2=0 is No Solution for x\in\mathbb{R}

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cos(2x)+sin(-x)-2=0

cos (2 x) + sin (- x) - 2 = 0

No Solution for x \in R

Solution steps

cos (2 x) + sin (- x) - 2 = 0

Rewrite using trig identities

- 1 - sin (x) - 2 sin^{2} (x) = 0

Solve by substitution

sin (x) = - \frac{1}{4} - i \frac{7}{4}, sin (x) = - \frac{1}{4} + i \frac{7}{4}

sin (x) = - \frac{1}{4} - i \frac{7}{4} :

No Solution

sin (x) = - \frac{1}{4} + i \frac{7}{4} :

No Solution

Combine all the solutions

No Solution for x \in R

sec (θ) = tan (θ)

- 3 csc (θ) = 2

sin (x) - 2 cos^{2} (x) = - 1

- 2 + 2 cos (x) + 4 cos^{2} (x) = 0

sin (A) = \frac{6.347}{12.7}

What is the general solution for cos(2x)+sin(-x)-2=0 ?
The general solution for cos(2x)+sin(-x)-2=0 is No Solution for x\in\mathbb{R}