What is the general solution for (sin(25)}{5.41}=\frac{sin(x))/9 ?

The general solution for (sin(25)}{5.41}=\frac{sin(x))/9 is x=0.77969…+360n,x=180-0.77969…+360n

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(sin(25)}{5.41}=\frac{sin(x))/9

\frac{sin ( 2 5 ^{\circ} )}{5.41} = \frac{sin ( x )}{9}

x = 0.77969 \dots + 36 0^{\circ} n, x = 18 0^{\circ} - 0.77969 \dots + 36 0^{\circ} n

Solution steps

\frac{sin ( 2 5 ^{\circ} )}{5.41} = \frac{sin ( x )}{9}

Switch sides

\frac{sin ( x )}{9} = \frac{sin ( 2 5 ^{\circ} )}{5.41}

Multiply both sides by

9

sin (x) = \frac{9 sin ( 2 5 ^{\circ} )}{5.41}

Apply trig inverse properties

x = arcsin (\frac{9 sin ( 2 5 ^{\circ} )}{5.41}) + 36 0^{\circ} n, x = 18 0^{\circ} - arcsin (\frac{9 sin ( 2 5 ^{\circ} )}{5.41}) + 36 0^{\circ} n

Show solutions in decimal form

x = 0.77969 \dots + 36 0^{\circ} n, x = 18 0^{\circ} - 0.77969 \dots + 36 0^{\circ} n

cos (θ) = \frac{4}{17}

- csc^{2} (x) + 2 csc (x) cot (x) = 0

6 sin (A) + 3 = 4 sin (A) + 4

a, - 10 = sin (a) + 15.2 cos (a)

0 = - 6 sin^{2} (θ) + 3 sin (θ) + 2

What is the general solution for (sin(25)}{5.41}=\frac{sin(x))/9 ?
The general solution for (sin(25)}{5.41}=\frac{sin(x))/9 is x=0.77969…+360n,x=180-0.77969…+360n