What is the general solution for cos(2x)=-0.35 ?

The general solution for cos(2x)=-0.35 is x=(1.92836…)/2+pin,x=-(1.92836…)/2+pin

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cos(2x)=-0.35

cos (2 x) = - 0.35

x = \frac{1.92836 \dots}{2} + πn, x = - \frac{1.92836 \dots}{2} + πn

Solution steps

cos (2 x) = - 0.35

Apply trig inverse properties

2 x = arccos (- 0.35) + 2 πn, 2 x = - arccos (- 0.35) + 2 πn

Solve

2 x = arccos (- 0.35) + 2 πn : x = \frac{arccos ( - 0.35 )}{2} + πn

Solve

2 x = - arccos (- 0.35) + 2 πn : x = - \frac{arccos ( - 0.35 )}{2} + πn

x = \frac{arccos ( - 0.35 )}{2} + πn, x = - \frac{arccos ( - 0.35 )}{2} + πn

Show solutions in decimal form

x = \frac{1.92836 \dots}{2} + πn, x = - \frac{1.92836 \dots}{2} + πn

0 = 3 sin (x + \frac{π}{2})

- cos (t) = cos (t)

sin^{2} (x) - cos (2 x) = - \frac{1}{4}

2 = cos^{2} (x) + sin^{2} (x)

- 5 π sin (\frac{π ( t )}{2}) = 7.071

What is the general solution for cos(2x)=-0.35 ?
The general solution for cos(2x)=-0.35 is x=(1.92836…)/2+pin,x=-(1.92836…)/2+pin