What is the general solution for 4sec(θ)+6=-2,0<= θ<2pi ?

The general solution for 4sec(θ)+6=-2,0<= θ<2pi is θ=(2pi)/3 ,θ=(4pi)/3

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4sec(θ)+6=-2,0<= θ<2pi

4 sec (θ) + 6 = - 2, 0 \leq θ < 2 π

θ = \frac{2 π}{3}, θ = \frac{4 π}{3}

Solution steps

4 sec (θ) + 6 = - 2, 0 \leq θ < 2 π

Move

6

to the right side

4 sec (θ) = - 8

Divide both sides by

4

sec (θ) = - 2

General solutions for

sec (θ) = - 2

θ = \frac{2 π}{3} + 2 πn, θ = \frac{4 π}{3} + 2 πn

Solutions for the range

0 \leq θ < 2 π

θ = \frac{2 π}{3}, θ = \frac{4 π}{3}

2 sin^{2} (x) - sin (x) = 0

cos (2 x) = - 0.35

0 = 3 sin (x + \frac{π}{2})

- cos (t) = cos (t)

sin^{2} (x) - cos (2 x) = - \frac{1}{4}

What is the general solution for 4sec(θ)+6=-2,0<= θ<2pi ?
The general solution for 4sec(θ)+6=-2,0<= θ<2pi is θ=(2pi)/3 ,θ=(4pi)/3