What is the general solution for sin(θ)=0.27,0<= θ<2pi ?

The general solution for sin(θ)=0.27,0<= θ<2pi is θ=0.27339…,θ=pi-0.27339…

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sin(θ)=0.27,0<= θ<2pi

sin (θ) = 0.27, 0 \leq θ < 2 π

θ = 0.27339 \dots, θ = π - 0.27339 \dots

Solution steps

sin (θ) = 0.27, 0 \leq θ < 2 π

Apply trig inverse properties

θ = arcsin (0.27) + 2 πn, θ = π - arcsin (0.27) + 2 πn

Solutions for the range

0 \leq θ < 2 π

θ = 0.27339 \dots, θ = π - 0.27339 \dots

tan (x) = 0.96

tan (x) = 0.87

4 sec (θ) + 6 = - 2, 0 \leq θ < 2 π

2 sin^{2} (x) - sin (x) = 0

cos (2 x) = - 0.35

What is the general solution for sin(θ)=0.27,0<= θ<2pi ?
The general solution for sin(θ)=0.27,0<= θ<2pi is θ=0.27339…,θ=pi-0.27339…