What is the general solution for solvefor y,(sqrt(3))/2 =sin(y) ?

The general solution for solvefor y,(sqrt(3))/2 =sin(y) is y= pi/3+2pin,y=(2pi)/3+2pin

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solvefor y,(sqrt(3))/2 =sin(y)

solvefor

y = \frac{π}{3} + 2 πn, y = \frac{2 π}{3} + 2 πn

Degrees

y = 6 0^{\circ} + 36 0^{\circ} n, y = 12 0^{\circ} + 36 0^{\circ} n

Solution steps

\frac{3}{2} = sin (y)

Switch sides

sin (y) = \frac{3}{2}

General solutions for

sin (y) = \frac{3}{2}

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

y = \frac{π}{3} + 2 πn, y = \frac{2 π}{3} + 2 πn

y = \frac{π}{3} + 2 πn, y = \frac{2 π}{3} + 2 πn

What is the general solution for solvefor y,(sqrt(3))/2 =sin(y) ?
The general solution for solvefor y,(sqrt(3))/2 =sin(y) is y= pi/3+2pin,y=(2pi)/3+2pin