What is the general solution for tan(β)=2,180<= β<= 270 ?

The general solution for tan(β)=2,180<= β<= 270 is β=1.10714…+180

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

tan(β)=2,180<= β<= 270

tan (β) = 2, 18 0^{\circ} \leq β \leq 27 0^{\circ}

β = 1.10714 \dots + 18 0^{\circ}

Radians

β = 1.10714 \dots + π

Solution steps

tan (β) = 2, 18 0^{\circ} \leq β \leq 27 0^{\circ}

Apply trig inverse properties

tan (β) = 2

General solutions for

tan (β) = 2

tan (x) = a \Rightarrow x = arctan (a) + 18 0^{\circ} n

β = arctan (2) + 18 0^{\circ} n

β = arctan (2) + 18 0^{\circ} n

Solutions for the range

18 0^{\circ} \leq β \leq 27 0^{\circ}

β = arctan (2) + 18 0^{\circ}

Show solutions in decimal form

β = 1.10714 \dots + 18 0^{\circ}

What is the general solution for tan(β)=2,180<= β<= 270 ?
The general solution for tan(β)=2,180<= β<= 270 is β=1.10714…+180