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Popular Trigonometry >

solvefor y,(sin(3y))/3 =(cos(2x))/2+1/2

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Solution

solvefor

Solution

y=3arcsin(23cos(2x)+3​)​+32πn​,y=3π​+3arcsin(−23cos(2x)+3​)​+32πn​
Solution steps
3sin(3y)​=2cos(2x)​+21​
Multiply both sides by 3
3sin(3y)​=2cos(2x)​+21​
Multiply both sides by 333sin(3y)​=3⋅2cos(2x)​+3⋅21​
Simplify
33sin(3y)​=3⋅2cos(2x)​+3⋅21​
Simplify 33sin(3y)​:sin(3y)
33sin(3y)​
Divide the numbers: 33​=1=sin(3y)
Simplify 3⋅2cos(2x)​+3⋅21​:23cos(2x)+3​
3⋅2cos(2x)​+3⋅21​
3⋅2cos(2x)​=23cos(2x)​
3⋅2cos(2x)​
Multiply fractions: a⋅cb​=ca⋅b​=2cos(2x)⋅3​
3⋅21​=23​
3⋅21​
Multiply fractions: a⋅cb​=ca⋅b​=21⋅3​
Multiply the numbers: 1⋅3=3=23​
=23cos(2x)​+23​
Apply rule ca​±cb​=ca±b​=23cos(2x)+3​
sin(3y)=23cos(2x)+3​
sin(3y)=23cos(2x)+3​
sin(3y)=23cos(2x)+3​
Apply trig inverse properties
sin(3y)=23cos(2x)+3​
General solutions for sin(3y)=23cos(2x)+3​sin(x)=a⇒x=arcsin(a)+2πn,x=π+arcsin(a)+2πn3y=arcsin(23cos(2x)+3​)+2πn,3y=π+arcsin(−23cos(2x)+3​)+2πn
3y=arcsin(23cos(2x)+3​)+2πn,3y=π+arcsin(−23cos(2x)+3​)+2πn
Solve 3y=arcsin(23cos(2x)+3​)+2πn:y=3arcsin(23cos(2x)+3​)​+32πn​
3y=arcsin(23cos(2x)+3​)+2πn
Divide both sides by 3
3y=arcsin(23cos(2x)+3​)+2πn
Divide both sides by 333y​=3arcsin(23cos(2x)+3​)​+32πn​
Simplifyy=3arcsin(23cos(2x)+3​)​+32πn​
y=3arcsin(23cos(2x)+3​)​+32πn​
Solve 3y=π+arcsin(−23cos(2x)+3​)+2πn:y=3π​+3arcsin(−23cos(2x)+3​)​+32πn​
3y=π+arcsin(−23cos(2x)+3​)+2πn
Divide both sides by 3
3y=π+arcsin(−23cos(2x)+3​)+2πn
Divide both sides by 333y​=3π​+3arcsin(−23cos(2x)+3​)​+32πn​
Simplifyy=3π​+3arcsin(−23cos(2x)+3​)​+32πn​
y=3π​+3arcsin(−23cos(2x)+3​)​+32πn​
y=3arcsin(23cos(2x)+3​)​+32πn​,y=3π​+3arcsin(−23cos(2x)+3​)​+32πn​

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