What is the general solution for 7cos(6x)=2 ?

The general solution for 7cos(6x)=2 is x=(1.28104…)/6+(pin)/3 ,x= pi/3-(1.28104…)/6+(pin)/3

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7cos(6x)=2

7 cos (6 x) = 2

x = \frac{1.28104 \dots}{6} + \frac{πn}{3}, x = \frac{π}{3} - \frac{1.28104 \dots}{6} + \frac{πn}{3}

Solution steps

7 cos (6 x) = 2

Divide both sides by

7

cos (6 x) = \frac{2}{7}

Apply trig inverse properties

6 x = arccos (\frac{2}{7}) + 2 πn, 6 x = 2 π - arccos (\frac{2}{7}) + 2 πn

Solve

6 x = arccos (\frac{2}{7}) + 2 πn : x = \frac{arccos ( \frac{2}{7} )}{6} + \frac{πn}{3}

Solve

6 x = 2 π - arccos (\frac{2}{7}) + 2 πn : x = \frac{π}{3} - \frac{arccos ( \frac{2}{7} )}{6} + \frac{πn}{3}

x = \frac{arccos ( \frac{2}{7} )}{6} + \frac{πn}{3}, x = \frac{π}{3} - \frac{arccos ( \frac{2}{7} )}{6} + \frac{πn}{3}

Show solutions in decimal form

x = \frac{1.28104 \dots}{6} + \frac{πn}{3}, x = \frac{π}{3} - \frac{1.28104 \dots}{6} + \frac{πn}{3}

sin^{2} (θ) + cos (θ) (1 - cos (θ)) = 0

tan (A) = \frac{94}{67}

2 tan (2 x) - 10 = 34641

cos (θ) = 0.5747

0 = \frac{110 cos ( 377 t )}{8}

What is the general solution for 7cos(6x)=2 ?
The general solution for 7cos(6x)=2 is x=(1.28104…)/6+(pin)/3 ,x= pi/3-(1.28104…)/6+(pin)/3