What is the general solution for sin^2(θ)+cos(θ)(1-cos(θ))=0 ?

The general solution for sin^2(θ)+cos(θ)(1-cos(θ))=0 is θ=(2pi)/3+2pin,θ=(4pi)/3+2pin,θ=2pin

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sin^2(θ)+cos(θ)(1-cos(θ))=0

sin^{2} (θ) + cos (θ) (1 - cos (θ)) = 0

θ = \frac{2 π}{3} + 2 πn, θ = \frac{4 π}{3} + 2 πn, θ = 2 πn

Solution steps

sin^{2} (θ) + cos (θ) (1 - cos (θ)) = 0

Rewrite using trig identities

1 + cos (θ) - 2 cos^{2} (θ) = 0

Solve by substitution

cos (θ) = - \frac{1}{2}, cos (θ) = 1

cos (θ) = - \frac{1}{2} : θ = \frac{2 π}{3} + 2 πn, θ = \frac{4 π}{3} + 2 πn

cos (θ) = 1 : θ = 2 πn

Combine all the solutions

θ = \frac{2 π}{3} + 2 πn, θ = \frac{4 π}{3} + 2 πn, θ = 2 πn

tan (A) = \frac{94}{67}

2 tan (2 x) - 10 = 34641

cos (θ) = 0.5747

0 = \frac{110 cos ( 377 t )}{8}

sin (2 x + 3) = 0.5

What is the general solution for sin^2(θ)+cos(θ)(1-cos(θ))=0 ?
The general solution for sin^2(θ)+cos(θ)(1-cos(θ))=0 is θ=(2pi)/3+2pin,θ=(4pi)/3+2pin,θ=2pin