What is the general solution for (sin(θ)+1)(sin(θ)-1)=0 ?

The general solution for (sin(θ)+1)(sin(θ)-1)=0 is θ=(3pi)/2+2pin,θ= pi/2+2pin

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(sin(θ)+1)(sin(θ)-1)=0

(sin (θ) + 1) (sin (θ) - 1) = 0

θ = \frac{3 π}{2} + 2 πn, θ = \frac{π}{2} + 2 πn

Solution steps

(sin (θ) + 1) (sin (θ) - 1) = 0

Solving each part separately

sin (θ) + 1 = 0 or sin (θ) - 1 = 0

sin (θ) + 1 = 0 : θ = \frac{3 π}{2} + 2 πn

sin (θ) - 1 = 0 : θ = \frac{π}{2} + 2 πn

Combine all the solutions

θ = \frac{3 π}{2} + 2 πn, θ = \frac{π}{2} + 2 πn

\frac{30}{sin ( x )} = \frac{50}{sin ( 9 0 ^{\circ} )}

cos (θ) = \frac{2 3}{5}

cos (2 x) (sin (x) + \frac{2}{2}) = 0

5 sin (θ) = 5

2 sin (3 x) = 2, 0 \leq x \leq 2 π

What is the general solution for (sin(θ)+1)(sin(θ)-1)=0 ?
The general solution for (sin(θ)+1)(sin(θ)-1)=0 is θ=(3pi)/2+2pin,θ= pi/2+2pin